Sb Sangpi
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 May 13 comment Find the value of $A$, $n$ and $b$ if $y=A\sin(nt)+b$ has range $[2,8]$ and period $\frac{2\pi}{3}$. sorry, no. I'm confuse. thx May 13 comment How to sketch $y=2\tan(x+\frac{\pi}{4})$ , $x \in (0,2\pi)$ yes! please provide me solution step by step. Appreciate it! May 13 comment How to sketch $y=2\tan(x+\frac{\pi}{4})$ , $x \in (0,2\pi)$ yes! sorry for my lack of maths knowledge. thx May 9 comment How to sketch $y=2\cos\,2x+3\sin\,2x$ , $x$ for $[-\pi,\pi]$. sorry. You are right.It is totally different! thx May 9 comment How to sketch $y=2\cos\,2x+3\sin\,2x$ , $x$ for $[-\pi,\pi]$. yea.when I read your answer, I understand it but compare to the answer graph.It make me confuse, the answer its the graph. thx@Arturo Magidin May 9 comment How to sketch $y=2\cos\,2x+3\sin\,2x$ , $x$ for $[-\pi,\pi]$. thx for that! Does your answer look the same as my graph. $y=3sin(2\theta)$ its not in the graph. thx May 9 comment How to sketch $y=2\cos\,2x+3\sin\,2x$ , $x$ for $[-\pi,\pi]$. sorry for that, intercepts for the graph. thx! May 9 comment How to sketch $y=2\cos\,2x+3\sin\,2x$ , $x$ for $[-\pi,\pi]$. yea, but can you please show me the working out. Sorry I'll be able to work out other questions as well. thx so much May 9 comment How to sketch $y=2\cos\,2x+3\sin\,2x$ , $x$ for $[-\pi,\pi]$. yea, exactly. Sorry for my lucky of maths. May 9 comment How to sketch $y=2\cos\,2x+3\sin\,2x$ , $x$ for $[-\pi,\pi]$. I think, it is almost the same? or totally different? May 8 comment List the $x$-axis intercepts for this trigonometric function yea! i think $cosx$=$\frac{\sqrt{2}}{\sqrt{2}}$ and its show in the unit cirle $\frac{7\pi}{4}$ May 2 comment Calculate all the values of $x$ between $0$ and $2\pi$, without using calculator. the answer is $\frac{\pi}{8}$ but I got $\frac{\pi}{4}$ May 1 comment Solve for $x$ in $[-\pi,\pi]$ @TheChaz so does the $x$ mean green lines from the above graph.thx May 1 comment Solve for $x$ in $[-\pi,\pi]$ ok! i got it one, but the other is when I look to $\frac{-\sqrt{3}}{2}$ it is not cos anymore, it is in $sin$ area. Apr 29 comment How to differentiate $x+\sqrt{1-x^2}$ yea. $u=(1-x^2)^\frac{1}{2}$ and $y=u^\frac{1}{2}$ , it is right? Apr 29 comment Find the value of $k$ when $x=1$ still $x=1$ is $\frac{-3k}{4}$ i can't get $-\frac{8}{3}$ Apr 28 comment Find the value of $k$ when $x=1$ edited, still wrong? Apr 28 comment Find the value of $k$ when $x=1$ edited, still can't get answer! thx Apr 28 comment Find the value of $k$ when $x=1$ edited mistake, still wrong? Apr 22 comment Find $g'(3)$ if $g(x)$ sorry 4 another question,i did this another question $\frac{3x+1}{f(x)}$ it doesn't work. can u help? thx