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Apr
2
accepted Why is $\frac{d}{d \mu} \big|_{\mu=0} \, F^*_\mu F^*_\lambda t = F^*_\lambda \frac{d}{d \mu} \big|_{\mu=0} \, F^*_\mu t $?
Apr
1
revised Why is $\frac{d}{d \mu} \big|_{\mu=0} \, F^*_\mu F^*_\lambda t = F^*_\lambda \frac{d}{d \mu} \big|_{\mu=0} \, F^*_\mu t $?
title
Dec
9
awarded  Caucus
Nov
25
comment Is there a codifferential for a covariant exterior derivative?
mathoverflow.net/questions/97061/… seems to answer the question but it does not explain how to extend Hodge star to bundle valued differential forms.
Nov
25
answered If $\operatorname{Def} X = \frac{1}{2} \mathcal L_X g$ then what is $\operatorname{Def}^* \operatorname{Def} X$?
Oct
20
asked If $\operatorname{Def} X = \frac{1}{2} \mathcal L_X g$ then what is $\operatorname{Def}^* \operatorname{Def} X$?
Oct
16
accepted Can a bilinear map on smooth functions induce a bilinear map on tensor fields in this way?
Oct
15
comment Can a bilinear map on smooth functions induce a bilinear map on tensor fields in this way?
to clarify terminology $(\alpha f + \beta g,h) = \alpha (f,h) + \beta (g,h)$ is linear over $\mathbb R$ if $\alpha, \beta \in \mathbb R$ (this one I meant) and over $C^\infty(M)$ if $\alpha, \beta \in C^\infty(M)$, right?
Oct
15
asked Can a bilinear map on smooth functions induce a bilinear map on tensor fields in this way?
Oct
6
accepted If $\operatorname{div} X = 0$ what can be said about $X^\flat$?
Oct
6
answered If $\operatorname{div} X = 0$ what can be said about $X^\flat$?
Oct
6
accepted Is there a Poincare lemma for codifferential?
Oct
6
revised Is there a codifferential for a covariant exterior derivative?
added 313 characters in body
Oct
6
asked Is there a Poincare lemma for codifferential?
Oct
3
comment Is there a codifferential for a covariant exterior derivative?
as well as math.stackexchange.com/questions/116554/…
Oct
3
comment Is there a codifferential for a covariant exterior derivative?
mathoverflow.net/questions/142913/… seems to be related
Oct
3
comment Is there a codifferential for a covariant exterior derivative?
Thank you. Right now even flat case would be nice. Do you have an explicit expression for $\delta^\nabla$? (it would probably require an extension of Hodge star operator).
Oct
3
comment Hodge decomposition on a manifold with a nontrivial connection
Have you figured this out since the question was asked?
Oct
3
asked Is there a codifferential for a covariant exterior derivative?
Oct
1
accepted What is the scalar product of tensors?