294 reputation
213
bio website stonehead.net
location Oslo, Norway
age 25
visits member for 3 years
seen Nov 15 '13 at 19:25

Student of music, math and sound recording.

@jodles89


Jul
2
awarded  Curious
Aug
15
comment A basic doubt on linear dependence of vectors
I think you mean "since t is not in the subspace spanned by u, v and w."
May
17
awarded  Caucus
May
8
awarded  Popular Question
Aug
20
awarded  Yearling
Dec
7
accepted Why is $\mathbf{\hat{x}} = \sum_{j=2}^n (\mathbf{x}\cdot\mathbf{u}_j)\mathbf{u}_j = \mathbf{x} - (\mathbf{x}\cdot \mathbf{u})\mathbf{u}$?
Dec
7
comment Why is $\mathbf{\hat{x}} = \sum_{j=2}^n (\mathbf{x}\cdot\mathbf{u}_j)\mathbf{u}_j = \mathbf{x} - (\mathbf{x}\cdot \mathbf{u})\mathbf{u}$?
Thanks, David! That's what I needed! Weird how it's so obvious after someone told you where to look...
Dec
7
asked Why is $\mathbf{\hat{x}} = \sum_{j=2}^n (\mathbf{x}\cdot\mathbf{u}_j)\mathbf{u}_j = \mathbf{x} - (\mathbf{x}\cdot \mathbf{u})\mathbf{u}$?
Dec
7
accepted Finding an orthogonal basis for an inner product space $\mathbf{P}_2$
Dec
6
asked Finding an orthogonal basis for an inner product space $\mathbf{P}_2$
Oct
21
accepted Different results for row reduction in Matlab
Oct
20
comment Different results for row reduction in Matlab
@J.M. I am using MATLAB 7.11.0 (R2010b).
Oct
20
revised Different results for row reduction in Matlab
Added screenshot from MATLAB
Oct
20
comment Different results for row reduction in Matlab
@J.M. and Agusti, I think I might have narrowed it down to a rounding error, causing the top and bottom row to be slightly different (but not shown due to lack of decimals shown in Matlab). As you are both more experienced here than me, do you think I should answer my own post or delete it? Thank you!
Oct
20
revised Different results for row reduction in Matlab
Possible solution
Oct
20
asked Different results for row reduction in Matlab
Oct
19
accepted Showing that $\{ 1, \cos t, \cos^2 t, \dots, \cos^6 t \}$ is a linearly independent set
Oct
10
comment Showing that $\{ 1, \cos t, \cos^2 t, \dots, \cos^6 t \}$ is a linearly independent set
Thank you for your answer, Arturo! I think my problem might stem from a misunderstanding of what linear independence requires. I thought for functions to be linearly independent, they need to be so for all $\mathbb{R}$; however, it seems like it's the other way around: i.e. if a set of functions are not linearly dependent for all $\mathbb{R}$, then they are linearly independent. So if we can show one example of linear independence, then we're done. Is that the gist of what you were saying?
Oct
10
comment Showing that $\{ 1, \cos t, \cos^2 t, \dots, \cos^6 t \}$ is a linearly independent set
Thank you for your answer, André! Forgive me for asking, but it is not obvious to me why the fact that $\cos t$ can take on more than 6 different values makes a contradiction?
Oct
8
asked Showing that $\{ 1, \cos t, \cos^2 t, \dots, \cos^6 t \}$ is a linearly independent set