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Jun
8
awarded  Caucus
Jun
1
comment Continuous and Open maps
A continuous function that maps open sets to open sets is just called an open map as far as I know.
Apr
20
comment Is there a way of defining the notion of a variable mathematically?
Thanks for the example. However, I am not convinced this clarifies what a variable is. Calling the symbol $x$ a variable when defining a polynomial ring $F[x]$ does not define what a variable is.
Apr
20
accepted Is there a way of defining the notion of a variable mathematically?
Apr
19
comment The topology of distributions
Excellent. Thanks.
Apr
19
comment Is there a way of defining the notion of a variable mathematically?
I do not see the connection. Can you give me a concrete example?
Apr
19
comment Is there a way of defining the notion of a variable mathematically?
I think I understand what you are getting at. If we take an informal expression with variables and make it formal ala metamath, we would get some string of symbols involving those variables, which is just a string in some formal language. Thus, in the language of metamath, a variable is any greek and roman letter that appears in a string of that language.
Apr
18
asked Is there a way of defining the notion of a variable mathematically?
Apr
18
revised The topology of distributions
deleted 59 characters in body
Apr
18
asked The topology of distributions
Apr
10
comment About the notation of the probability measures
It should be since $P^{X_n}$ is a measure on the image space of $X_n$.
Apr
6
accepted Given $\int_0^x f(t) \, dt = 2\cos x + 3x + 2,$ find $f$
Apr
6
comment Given $\int_0^x f(t) \, dt = 2\cos x + 3x + 2,$ find $f$
You are absolutely right. Thank you for pointing this out.
Apr
6
comment Given $\int_0^x f(t) \, dt = 2\cos x + 3x + 2,$ find $f$
It didn't occur to me to check the first equation. I knew something was fishy. I am convinced that it is a typo. Thanks.
Apr
6
asked Given $\int_0^x f(t) \, dt = 2\cos x + 3x + 2,$ find $f$
Feb
3
accepted Characters and permutation matrices
Feb
2
comment Characters and permutation matrices
Are saying that because the permutation representation is reducible, $\chi$ is not a bonafide "character"?
Feb
2
comment Characters and permutation matrices
So you are saying that it should be $\chi(gg^{-1})=\chi(g)+\chi(g^{-1})$? And what do you mean by "characters of degree 1"? Aren't all characters one-dimensional representations?
Feb
2
asked Characters and permutation matrices
Dec
14
accepted dy/dx when x and y are functions