Nicolas Essis-Breton
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 May20 accepted Finding the range of a vector valued function May20 comment Finding the range of a vector valued function What is then the conclusion, once $\det J_f=0$ on the line $y=x$? May20 revised Finding the range of a vector valued function added 83 characters in body May20 asked Finding the range of a vector valued function May20 awarded Constituent May17 accepted Vector valued Mean value theorem: Norm for the gradient May17 revised Vector valued Mean value theorem: Norm for the gradient added 29 characters in body May17 asked Vector valued Mean value theorem: Norm for the gradient May17 accepted Show $5z^n=e^z$ has a finite number of zero in $\{a<\Im z < v\}$ and $\{a < \Re z < b \}$ May16 asked What is the function given by $\sum_{n=0}^\infty \binom{b+2n}{b+n} x^n$, where $b\ge 0$, $|x| <1$ May16 accepted Show the map $f(x)=\frac12 (x+1/x)$ has an attractive fixed point in $(0,\infty)$ May16 asked Show the map $f(x)=\frac12 (x+1/x)$ has an attractive fixed point in $(0,\infty)$ May13 comment Maximum likelihood in exponential family: $\partial_{\theta,\theta} \ln L = -\mathrm{Var}(T)$, $T$ sufficient for $\theta$ @Caran-d'Ache I think you mean $$\mathrm{Var}(T) \ge (E(-\partial_{\theta,\theta} \ln L))^{-1},$$ the Cramer-Rao lower for the variance of $T$. From my calculation, this works, and it explains why they are inverse of each other. Thanks for your input, combine with Did comment, I better understand what is going on. May13 accepted Mean number of particle present in the system: birth-death process, $E(X_t|X_0=i)$, $b_i=\frac{b}{i+1}$, $d_i=d$ May12 asked Maximum likelihood in exponential family: $\partial_{\theta,\theta} \ln L = -\mathrm{Var}(T)$, $T$ sufficient for $\theta$ May9 asked Mean number of particle present in the system: birth-death process, $E(X_t|X_0=i)$, $b_i=\frac{b}{i+1}$, $d_i=d$ May7 awarded Popular Question May7 awarded Caucus May6 revised show $\frac{1}{n}\sum (X_i - \mu_i) \xrightarrow{L^2} 0$, $X_i$ independent with mean $\mu_i$ added 5 characters in body May6 asked show $\frac{1}{n}\sum (X_i - \mu_i) \xrightarrow{L^2} 0$, $X_i$ independent with mean $\mu_i$