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Sophomore Graduate Student in Mathematics


Feb
19
comment No Bijection from set $X$ to $X - \{x\}$
Is a proof possible without some form of cardinality being brought into picture?
Feb
12
comment Proving upper bounds?
@HagenvonEitzen Wow!!
Feb
12
comment Is there an axiom that prevents other axioms from contradicting each other?
en.wikipedia.org/wiki/Three_classic_laws_of_thought
Feb
5
comment When $dy/dx =0$ for all $x$ in the domain, is $dx/dy$ also zero?
+1 For the proper explanation.
Feb
1
comment Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
Yes. I am Jayesh. Name changed for a month.
Feb
1
comment Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
Nice solution Chris'ssister! :-) Your question and the corresponding answers provide a decent tool. :-)
Feb
1
comment Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
Thanks. A different solution. :-)
Feb
1
comment Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
Okay. No problems. :-) Generally, when people downvote, and the OP asks the reason, it is expected that the person who downvoted leave a comment about it. And hence, my assumption.
Feb
1
comment Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
Arrrrgh. Thanks.
Feb
1
comment Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
@ToddWilcox Counterpoint. meta.math.stackexchange.com/q/2244/14082
Feb
1
comment Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
Added the explanation. I hope its correct.
Feb
1
comment Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
A few reasons 1. It gives me oppurtunity to verify that the solution is indeed correct. (I self study, so even though I get an answer and I am pretty sure about it, there is no real way to verify the solution completely.) 2. It allows probably other people to offer me better solutions. 3. I can do so on a blog, but then it might not get the same attention on the blog. 4. MSE's editing capabilities are better than almost all other blogging software I have found.
Feb
1
comment Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
Is the downvote because of self-answering?
Jan
4
comment Calculating the integral $\int_0^{\infty}{\frac{\ln x}{1+x^n}}$ using complex analysis
Awesome answer.
Dec
26
comment How to check if a point is inside a rectangle?
Excellent answer.
Dec
6
comment Subscript in maximum notation
If you found the answer to be correct and helpful, you might want to accept it by clicking the "Right" sign besides the answer. :-)
Dec
4
comment Properties about Matrices that can be proved by only using Block Multiplication of Matrices
@joriki yes, I rewrote the sentence. I hope this formulates my problem better.
Nov
26
comment Compute $\lim_{n\to\infty}(n-(\arccos(1/n)+\cdots+\arccos(n/n)))$
That the error part decreases as $1/N^2$ is decisive for the proof. Nice. :-)
Nov
15
comment Information on the sum $\sum_{n=1}^\infty \frac{\log n}{n!}$
@did Sorry, you misunderstood me. I wanted to ask the reason for your comment "What is the meaning of "play with formulas equivalent to the original question and bringing no new information nor understanding to it"? "
Nov
15
comment Information on the sum $\sum_{n=1}^\infty \frac{\log n}{n!}$
@did Complete noob here. So may I ask you to explain why the two formulas are equivalent? I have got a suspicion it is so because it is basically just replacing formulas with numbers? Am I correct? For example, is this similar to saying that $\sum_{n=0}^\infty \frac{1}{n!} = e$?