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Sophomore Graduate Student in Mathematics


Oct
5
awarded  Organizer
Oct
5
revised Prove that exists a unique subgroup $H$ of $G$ has order of $n$.
Corrected a minor grammatical error in the title and the text and tagged the question with abstract algebra tag to better mirror the background.
Oct
5
suggested suggested edit on Prove that exists a unique subgroup $H$ of $G$ has order of $n$.
Oct
4
comment Dual basis of a shrinking unconditional basis
@TrzyTrypy You can delete the question yourself and that would be the best method to do so.
Sep
28
comment Cycling Digits puzzle
Added some more explanation. I hope it is more clear now.
Sep
28
revised Cycling Digits puzzle
added 134 characters in body
Sep
28
revised Cycling Digits puzzle
added 18 characters in body
Sep
28
revised Cycling Digits puzzle
added 18 characters in body
Sep
28
revised Cycling Digits puzzle
added 631 characters in body
Sep
28
revised Cycling Digits puzzle
added 631 characters in body
Sep
28
comment Cycling Digits puzzle
@PerManne Yup. Sorry about that, I was going to update it.
Sep
28
answered Cycling Digits puzzle
Sep
28
revised Combinatorial argument to prove the recurrence relation for number of derangements
added 40 characters in body
Sep
28
answered Combinatorial argument to prove the recurrence relation for number of derangements
Sep
27
awarded  Cleanup
Sep
26
comment field generated by a set
Where I mean $K$ by $G_{S}$
Sep
26
comment field generated by a set
@JasonDeVito I guess your objection is invalid, since we are talking about $S$ generating $R$, rather than $S$ being $R$ itself. Since, if $\frac{1}{10} \in S$ then $\frac{k}{10} \in G_{S}$ where $k \in Z$.
Sep
26
comment field generated by a set
@FortuonPaendrag You say that your proof is flawed. I think it would be good if you can probably indicate why do you think it is flawed in the answer itself.
Sep
25
revised In what spaces does the Bolzano-Weierstrass theorem hold?
Changed the complete nature of the answer to reflect the comments.
Sep
25
comment In what spaces does the Bolzano-Weierstrass theorem hold?
@KevinCarlson Its okay. I do not mind.