Reputation
1,501
Top tag
Next privilege 2,000 Rep.
 Jan 18 revised Bounds for solutions of $xe^{x} -n =0$ for $n\geq 3$ Made the title more informative. Jan 18 suggested approved edit on Bounds for solutions of $xe^{x} -n =0$ for $n\geq 3$ Jan 16 awarded Informed Jan 7 awarded Nice Answer Jan 7 revised Prove that $x = 2$ is the unique solution to $3^x + 4^x = 5^x$ where $x \in \mathbb{R}$ added 2 characters in body Jan 7 answered Prove that $x = 2$ is the unique solution to $3^x + 4^x = 5^x$ where $x \in \mathbb{R}$ Jan 4 comment Calculating the integral $\int_0^{\infty}{\frac{\ln x}{1+x^n}}$ using complex analysis Awesome answer. Dec 6 comment Subscript in maximum notation If you found the answer to be correct and helpful, you might want to accept it by clicking the "Right" sign besides the answer. :-) Dec 4 comment Properties about Matrices that can be proved by only using Block Multiplication of Matrices @joriki yes, I rewrote the sentence. I hope this formulates my problem better. Dec 4 revised Properties about Matrices that can be proved by only using Block Multiplication of Matrices deleted 193 characters in body Dec 4 asked Properties about Matrices that can be proved by only using Block Multiplication of Matrices Dec 1 awarded Popular Question Nov 26 comment Compute $\lim_{n\to\infty}(n-(\arccos(1/n)+\cdots+\arccos(n/n)))$ That the error part decreases as $1/N^2$ is decisive for the proof. Nice. :-) Nov 17 revised Is memory unimportant in doing mathematics? added 257 characters in body Nov 17 answered Is memory unimportant in doing mathematics? Nov 15 comment Information on the sum $\sum_{n=1}^\infty \frac{\log n}{n!}$ @did Sorry, you misunderstood me. I wanted to ask the reason for your comment "What is the meaning of "play with formulas equivalent to the original question and bringing no new information nor understanding to it"? " Nov 15 comment Information on the sum $\sum_{n=1}^\infty \frac{\log n}{n!}$ @did Complete noob here. So may I ask you to explain why the two formulas are equivalent? I have got a suspicion it is so because it is basically just replacing formulas with numbers? Am I correct? For example, is this similar to saying that $\sum_{n=0}^\infty \frac{1}{n!} = e$? Nov 15 accepted $I_m - AB$ is invertible if and only if $I_n - BA$ is invertible. Nov 15 comment $I_m - AB$ is invertible if and only if $I_n - BA$ is invertible. This is how I did the problem the first time, but then I forgot how I did it and was stuck. :P Thanks :-) Nov 15 comment $I_m - AB$ is invertible if and only if $I_n - BA$ is invertible. Thank you for another nice answer.