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Sophomore Graduate Student in Mathematics


Feb
2
reviewed Excellent Uniformization Theorem for compact surface
Feb
2
reviewed Excellent Compact linear operator from $L^p (\mathbb R)$ to $L^p (\mathbb R)$
Feb
2
reviewed Excellent Limit Computation of $(e^x+x)^{1/x}$ as $x$ approaches zero
Feb
2
reviewed Satisfactory Find the coordinates of a point on a circle
Feb
2
reviewed Excellent Logic about systems?
Feb
1
revised Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
Added the link to your result so that people can understand the result directly instead of hunting for it in the comments. :-)
Feb
1
suggested approved edit on Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
Feb
1
comment Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
Yes. I am Jayesh. Name changed for a month.
Feb
1
accepted Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
Feb
1
comment Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
Nice solution Chris'ssister! :-) Your question and the corresponding answers provide a decent tool. :-)
Feb
1
awarded  Self-Learner
Feb
1
revised Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
added 44 characters in body
Feb
1
revised Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
deleted 201 characters in body
Feb
1
comment Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
Thanks. A different solution. :-)
Feb
1
revised Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
added 155 characters in body
Feb
1
comment Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
Okay. No problems. :-) Generally, when people downvote, and the OP asks the reason, it is expected that the person who downvoted leave a comment about it. And hence, my assumption.
Feb
1
revised Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
deleted 204 characters in body
Feb
1
comment Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
Arrrrgh. Thanks.
Feb
1
comment Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
@ToddWilcox Counterpoint. meta.math.stackexchange.com/q/2244/14082
Feb
1
comment Limit of $s_n = \int\limits_0^1 \frac{nx^{n-1}}{1+x} dx$ as $n \to \infty$
Added the explanation. I hope its correct.