network profile
| bio | website | |
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| age | ||
| visits | member for | 1 year, 9 months |
| seen | Jul 30 '11 at 14:12 | |
| stats | profile views | 5 |
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Jan 11 |
awarded | Popular Question |
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Jul 29 |
comment |
how to calculate the angle in the x-y, y-z, x-z plane given only 3D vector direction and magnitude? Am I on the right track on this or not? |
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Jul 29 |
comment |
how to calculate the angle in the x-y, y-z, x-z plane given only 3D vector direction and magnitude? ..also, the length of the cone does not change as it cuts the x-y plane-- so this reduces the problem to a 2D problem in the x-y plane with both magnitude and angle wrt to x-axis specified. Then using simple trig (R cos phi) we can find x-component of this 3-D vector R. |
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Jul 29 |
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how to calculate the angle in the x-y, y-z, x-z plane given only 3D vector direction and magnitude? Wow this post has been a big help. If I understand direction cosines right, it is similar to imagining a cone whose dimensions are given by 3-D vector and angle wrt x-axis say (lets call this vector R and angle phi). Now, if we imagine the cone completing a revolution around the x-y plane, and we ask ourselves at what angle wrt x-axis does the cone cut through the x-y plane -- it is the same angle as phi. |
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Jul 28 |
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how to calculate the angle in the x-y, y-z, x-z plane given only 3D vector direction and magnitude? I am sorry about that. I can see how the vector is not fixed in space and can be anywhere on a cone with the given angle wrt to x-axis. I will try to figure out if there is more information to the vector that I can find in order to fix its location in 3-D space. |
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Jul 28 |
asked | how to calculate the angle in the x-y, y-z, x-z plane given only 3D vector direction and magnitude? |
