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Jul
14
revised Determining the best possible constant $k$, for an Integral Inequality
carry an edit through and add an approximation
Jul
14
comment Determining the best possible constant $k$, for an Integral Inequality
@T.Bongers: did you get that with a test function?
Jul
14
answered Determining the best possible constant $k$, for an Integral Inequality
Jul
13
revised Interesting Sum Congruence
justify $(4)$
Jul
13
revised Interesting Sum Congruence
make division by 12 legal
Jul
13
answered Interesting Sum Congruence
Jul
12
revised What is the efficient way to calculate number of divisors of N that are divisible by 2?.
note contest
Jul
12
comment Algebraic Vectors in r cubed plane
We prefer to not delete good content. This answer may be useful to future readers, so it has been undeleted.
Jul
12
comment Weak Amalgamation Property for Boolean algebras
Please avoid making trivial edits just to keep the question on the front page. Either wait until you have a significant improvement to make or offer a bounty to get more attantion to your question.
Jul
11
awarded  Nice Answer
Jul
11
comment Formula for Sum of Logarithms $\ln(n)^m$
The main complaint about my answer was that the OP wanted an exact formula, like we have for $m=1$ and $\log(k!)$. I haven't had a chance to look very closely at your answer yet. Does it provide an exact answer, or a series (infinite sum) approximation?
Jul
11
revised Proof about AM-GM inequality generalized
handle various signs of $p$ and $q$ better
Jul
11
revised Proof about AM-GM inequality generalized
handle various signs of $p$ and $q$ better
Jul
10
answered Show a function is monotonically decreasing.
Jul
10
comment Prove that $f$ is constant on $[a,b]$
If the integral of the square of $f$ is $0$, then $f$ is $0$ almost everywhere. Continuity handles the rest.
Jul
10
revised Proof about AM-GM inequality generalized
add a justification for $p=0$
Jul
10
answered Proof about AM-GM inequality generalized
Jul
10
comment Proof about AM-GM inequality generalized
@Ant: consider $\{1/2,1/2,-1\}$. The arithmetic mean is $0$ but the harmonic mean is $1$.
Jul
10
revised How to find $\sum_{k \in \mathbb{Z}}\frac1{(k+a)(k+b)}$
add some steps to make things clearer
Jul
10
answered How to find $\sum_{k \in \mathbb{Z}}\frac1{(k+a)(k+b)}$