Reputation
1,030
Next privilege 2,000 Rep.
Edit questions and answers
Badges
1 10 22
Newest
 Necromancer
Impact
~75k people reached

Jul
30
comment $a,b,c>0 \text{ s.t. }a+b+c=1 \implies \sqrt{ab+c}+\sqrt{bc+a}+\sqrt{ca+b} \ge 1+ \sqrt{ab}+\sqrt{bc}+\sqrt{ca}$
Thank you very much.I managed to prove this but my method was really ugly.Thanks for the solution again!
Jul
30
awarded  Student
Jul
30
asked $a,b,c>0 \text{ s.t. }a+b+c=1 \implies \sqrt{ab+c}+\sqrt{bc+a}+\sqrt{ca+b} \ge 1+ \sqrt{ab}+\sqrt{bc}+\sqrt{ca}$