Richard Inglis
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 Feb4 awarded Popular Question Dec16 awarded Notable Question Oct30 awarded Autobiographer Oct15 awarded Popular Question Feb20 revised Numerical approximation of Levy Flight Added Matlab code Feb12 comment Numerical approximation of Levy Flight Hi @Asad Ali: the power law distribution is used to control the length of each step (always positive), but each step is in a random direction (see second paragraph in my question above), which produces a 2-d path. I will try to find some matlab code for you (but it might take a day or so!). Jul21 awarded Yearling Sep22 accepted normal vector to surface $z=\frac{-1}{\sqrt{x^2+y^2}}$ Sep22 awarded Commentator Sep22 comment normal vector to surface $z=\frac{-1}{\sqrt{x^2+y^2}}$ Sep22 comment normal vector to surface $z=\frac{-1}{\sqrt{x^2+y^2}}$ Brain and laptop both about to run out of batteries... thanks for your help anon - I'll have to try to work out the rest tomorrow. Sep22 comment normal vector to surface $z=\frac{-1}{\sqrt{x^2+y^2}}$ I'm getting something like $(x^{-2},y^{-2},1)$... Sep22 comment normal vector to surface $z=\frac{-1}{\sqrt{x^2+y^2}}$ @anon: um, $z+(x^2+y^2)^{-1/2}=0$, but it may take me several days to differentiate it... :) Sep22 comment normal vector to surface $z=\frac{-1}{\sqrt{x^2+y^2}}$ Is it $\nabla F(a)=(\frac{\partial F}{\partial x},\frac{\partial F}{\partial y},\frac{\partial F}{\partial z})$? Sep22 comment normal vector to surface $z=\frac{-1}{\sqrt{x^2+y^2}}$ Ok, but how do I work out $\nabla F(a)$? Sorry, my maths is very rusty... Sep22 asked normal vector to surface $z=\frac{-1}{\sqrt{x^2+y^2}}$ Sep13 accepted Name for $(1-x)$? Sep13 accepted Fitting an exponential function to data Sep13 awarded Nice Question Sep12 comment Name for $(1-x)$? @Rasmus: ...and what's the word to describe that property?