154 reputation
10
bio website franklyanything.com/blog
location Seattle, WA
age
visits member for 3 years, 1 month
seen Aug 14 at 3:29

Marketing professional in the video game industry. iOS hacker by night.


Jul
6
accepted Express $3.72444\ldots$ as a fraction using the formula for geometric progressions
Jul
6
asked Express $3.72444\ldots$ as a fraction using the formula for geometric progressions
Jul
5
accepted Why is this not the simplest form of this expression?
Jul
5
comment Why is this not the simplest form of this expression?
It does not, and so perhaps I was reading too much into it.
Jul
5
comment Why is this not the simplest form of this expression?
Interesting, I hadn't thought of that. The series to be solved was $\sqrt{12}+\sqrt{6}+\sqrt{3}+...$ Given that, I'm not seeing a connection between the first term and the ratio. Or am I overlooking it?
Jul
5
comment Why is this not the simplest form of this expression?
Hmmm...maybe I'm confused about what it means for an expression to be in simplest form. I guess I thought of addition as being simpler than multiplication.
Jul
5
asked Why is this not the simplest form of this expression?
Jul
4
accepted Algebraic Symbol Manipulation While Finding the Sum of a Series
Jul
4
comment Algebraic Symbol Manipulation While Finding the Sum of a Series
Eeesh. Of course. Thank you.
Jul
4
comment Algebraic Symbol Manipulation While Finding the Sum of a Series
Are you saying I have the wrong value for $r$? That it should be $1-\frac{1}{\sqrt{3}}$? If so can you help me understand why. Thanks!
Jul
4
asked Algebraic Symbol Manipulation While Finding the Sum of a Series
Jul
2
awarded  Curious
Jun
26
answered Summing a Geometric Series
Jun
22
asked Summing a Geometric Series
Jun
18
accepted Using Remainder or Factor Theorems to Find Coefficient
Jun
18
comment Using Remainder or Factor Theorems to Find Coefficient
Thanks. I think I'm not fully understanding what it means for something to be a 'root'.
Jun
18
asked Using Remainder or Factor Theorems to Find Coefficient
Jun
13
comment Help with Evaluating a Logarithm
Thanks so much. Of course $\sqrt[3]{2^2} = \sqrt[3]{2}\cdot\sqrt[3]{2}$ So obvious in retrospect. Thanks again!
Jun
13
accepted Help with Evaluating a Logarithm
Jun
13
asked Help with Evaluating a Logarithm