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| bio | website | |
|---|---|---|
| location | ||
| age | ||
| visits | member for | 1 year, 10 months |
| seen | May 19 at 6:12 | |
| stats | profile views | 2,114 |
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Jul 2 |
comment |
Area computed using polar coordinates @ArturoMagidin The formula isn't the problem. I have tried it with the correct formula, I just typed it up wrong. |
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Jul 2 |
revised |
Area computed using polar coordinates deleted 10 characters in body |
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Jul 2 |
revised |
Area computed using polar coordinates added 348 characters in body; added 25 characters in body |
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Jul 2 |
asked | Area computed using polar coordinates |
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Jul 2 |
accepted | Area of polar coordinate $r = e^{- \theta/4}$ |
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Jul 2 |
comment |
Area of polar coordinate $r = e^{- \theta/4}$ I was attempting to work my way through how to do that so I did $2^3^2$ on my calculator and it gave me 512 which means that it is $2^9$ which means that I have to square the exponent. What went wrong? |
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Jul 2 |
asked | Area of polar coordinate $r = e^{- \theta/4}$ |
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Jul 1 |
accepted | Polar equation of cartesian $y = 1 + 3x$ |
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Jul 1 |
asked | Polar equation of cartesian $y = 1 + 3x$ |
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Jul 1 |
accepted | Polar equation of $y = 2$ |
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Jul 1 |
comment |
Polar equation of $y = 2$ So all you did was divide everything by sin? |
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Jul 1 |
comment |
Polar equation of $y = 2$ Where does csc come from and what does p represent differently than r? |
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Jul 1 |
asked | Polar equation of $y = 2$ |
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Jun 26 |
accepted | Solve $y' = x + y$ |
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Jun 25 |
asked | Parametric equations and area |
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Jun 25 |
accepted | Finding $\frac{d^2 y}{dx^2}$ |
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Jun 25 |
comment |
Finding $\frac{d^2 y}{dx^2}$ I do not understand the d/dt part, what that means and how I calculate that. |
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Jun 25 |
asked | Finding $\frac{d^2 y}{dx^2}$ |
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Jun 25 |
accepted | Centroid of a region |
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Jun 25 |
accepted | Parametric equations and line segments |
