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May
26
comment Amicable pair sums - intriguing sexagesimal relationships
$\sigma(m)=\sigma(n) = m+n was meant
May
26
comment Amicable pair sums - intriguing sexagesimal relationships
Please help me out with te Riele's paper. He defines an amicable pair as $\sigma(m)=\sigma(n) = m+n, whereas I've understood it to be the sum of m's divisors equalling n, and n's equalling m.
May
25
comment Amicable pair sums - intriguing sexagesimal relationships
Most the pair sums I've looked at in response to your answer so far are smoother than either of the two numbers in the pair concerned, or at least have a greatest prime factor smaller than the average gpf of the two numbers. That is, if amicable sum m + n is k smooth, then k < (j+l)/2 iff m is j smooth and n is l smooth. Summing AP's seems to be a way of smoothing out, reducing the incidence of big lumpy primes. Getting lots of small ones instead: 2's, 3's, 5's, makes it less surprising to get multiples and powers of 6 and 10 so frequently.
Apr
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revised Is there any geometry where ratio of circle's circumference to its diameter is rational?
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Apr
22
answered Is there any geometry where ratio of circle's circumference to its diameter is rational?
Mar
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awarded  Peer Pressure
Mar
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comment Split number in two, so that two rounded portions equal the original.
The algebra simplifies things: 2((a/2)+b) is greater than a, where a and b are greater than 0.
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revised Split number in two, so that two rounded portions equal the original.
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Feb
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answered Split number in two, so that two rounded portions equal the original.
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