Christian Ivicevic
Reputation
868
Top tag
Next privilege 1,000 Rep.
Create tags
 Jun11 comment Partial fractions for geometric probability-generating function wrong @anon: Thanks. Answered my own question now. Jun11 comment Explanation of Zeta function and why 1+2+3+4+… = -1/12 @MattE: During creation of my thread the search didn't reveal any duplicate topic, but thanks for the ref to your answer. I'll be fine with it, although it takes its time to be understood. Could you link your other answer as an answer here? (Or shall we close this topic?) And thanks to you, Peter, too. Jun11 comment Explanation of Zeta function and why 1+2+3+4+… = -1/12 @PeterTamaroff: If this is something like the computation of $\lim\limits_{x\to 0}\sin(x)/x=1$ then yes; otherwise I'm afraid not. May21 comment Pumping lemma for regular “pumped formal language” nothing to do here. However I am fine waiting a little bit for an answer as it is not urgent! Neither should I get full solutions for homework. But thanks for the hint as CSTheory and the hint for the homework. May20 comment Pumping lemma for regular “pumped formal language” @DavidLewis: Should I repost this question or can i move it there? May20 comment Pumping lemma for regular “pumped formal language” @Gigili: I am not allowed to ask homework-related questions there. The FAQ doesn't allow it! May19 comment Transformation of first moment @DilipSarwate: Thats a really good hint (almost a full solution!). Shame on me why I haven't understood it before. This should result in $\mathbb{E}[A]=0.3$, shouldn't it? Dec4 comment Computation of coefficients of Lagrange polynomials Our homework is divided into the Lagrage part and then the Aitken-Neville and then Newton part. Therefore we need to try all methods ;-) But i will have a look at the paper you provided! Dec4 comment Computation of coefficients of Lagrange polynomials I have implemented a Polynomial class which has the eval method based on the Horner scheme. Do you think, that i should use this? My first thought was to check whether i can get the coefficients with a more efficient algorithm rather then evaluating something... furthermore, while writing this, i need to remember the exact task. We must create the polynomial without a specific $x$. That is the reason why we have a Polynomial class. This is where my intention comes from to directly compute the coeffs. Dec4 comment Computation of coefficients of Lagrange polynomials I could do that, but want to avoid that. We should implement this in Java for our Numerics lecture and we learned that it is a pain to derive as there many small errors can extremely influence the result! So i wanted a "small" expression that can be easily evaluted. Nov29 comment Is $n=\mathcal{O}(n+1)$? This notation is weird I know, so i will change this one. In a few minutes I will accept your answer, when the system allows me to do so. Nov1 comment Limit proof of a sqrt-heavy expression with binomial formula / sandwich-rule @CaptainGiraffe: By obvious I mean that if you think aboout it, there is something about this idea. Furthermore I checked the limit with Mathematica and know that $\sqrt{2}$ is the solution. Nov1 comment Limit proof of a sqrt-heavy expression with binomial formula / sandwich-rule +1 for the explanation of the method my fellow students used! However, as you already mentioned, I sticked to the conjugate quantity method which was much easier ;) Nov1 comment Limit proof of a sqrt-heavy expression with binomial formula / sandwich-rule Although I never heard of either these methods, the first one seems the most convenient and human-readable one which solves my problem here! After reading the Wikipedia article this will be the solution I will use. Thanks! Oct31 comment Proof for convergence of a given progression $a_n := n^n / n!$ Interesting approach, but the other hints were much easier to use. Sorry. Oct8 comment Function as parameter in Wolfram Mathematica Is there any way, like in programming languages, to define an "anonymous function" (a.k.a. lambda-expression) the way i tried? Oct8 comment Function as parameter in Wolfram Mathematica It does not work like expected! E.g. $E(f)(x)$ is now called TranslateEx. TranslateEx[fn_] := Apply[fn, {x + 1}] and then TranslateEx[x] leads to the result x[1 + x]. What does this mean? I expected x + 1 as the result. EDIT It seems i cannot enter a function directly and i need to specify it explicitly... Oct2 comment Transform uniform distribution to normal distribution using Lindeberg–Lévy CLT @cardinal: My ranges are sometimes different. It might happen, that i want to pick a number out of [1;20] and sometimes out of [1;100]. Which technique is used to compute the most convenient standard deviation because there are many numbers left out if i use a wide interval and $a=\sigma=1$. Oct2 comment Transform uniform distribution to normal distribution using Lindeberg–Lévy CLT @cardinal: I tried Box-Muller, however i was not able to shift the median like with Marsaglia! And if i think about the scenario: in the time i compute 1.000 uniform numbers i will need... 10 normal ones and i am confident, that i will be have with this :) Oct2 comment Transform uniform distribution to normal distribution using Lindeberg–Lévy CLT @Gortaur: I have a solution - please have a look at my question which is edited now.