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 Dec16 awarded Popular Question Oct11 awarded Notable Question Jul2 awarded Curious Feb27 awarded Notable Question Feb18 awarded Popular Question Oct23 awarded Notable Question Oct21 awarded Popular Question Sep23 awarded Popular Question Sep18 awarded Popular Question Jun9 awarded Yearling Jan15 awarded Popular Question Aug3 awarded Nice Question Jul7 awarded Popular Question Jun9 awarded Yearling Jul31 awarded Nice Question Jul31 comment Proving that $(b_n) \to b$ implies $\left(\frac{1}{b_n}\right) \to \frac{1}{b}$ This makes sense, thank you. You are right, picking a smaller epsilon actually leads me closer to the sequence, I missed that at first. Thanks again! Jul31 accepted Proving that $(b_n) \to b$ implies $\left(\frac{1}{b_n}\right) \to \frac{1}{b}$ Jul31 revised Proving that $(b_n) \to b$ implies $\left(\frac{1}{b_n}\right) \to \frac{1}{b}$ added 1 characters in body Jul31 asked Proving that $(b_n) \to b$ implies $\left(\frac{1}{b_n}\right) \to \frac{1}{b}$ Jul28 awarded Nice Question