Brian M. Scott
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# 380,852 Reputation

10 today
 +10 6 hours ago upvote What is a saturation of a set?
355 yesterday
 +35 04:42 3 events Prove that all trees are bipartite +35 03:01 3 events Set theory: how to interpret multiple quantifiers +25 21:09 2 events Matrix-Tree Theorem: proof with graph characteristic polynomial +25 17:07 2 events Regular expression that begins and ends with digit +25 10:21 2 events Equivalent Condition for Connectedness +25 09:17 2 events Sequential Test: If $\forall x_n \in D\backslash\{c\}, \lim_{n\to \infty}x_n = c \implies \lim_{n \to \infty} f(x_n)=L$, then $\lim_{x\to c}f(x) = L$. +25 06:24 2 events How to find documentation for or a proof of the following known binomial identity +25 04:24 2 events A question about retraction mapping +15 19:54 accept Trouble deriving the Catalan numbers (near the last step) +15 12:59 accept Isi B.Math Fibonacci problem. +15 02:41 accept How can these row-equivalent matrices have the same determinant? +10 20:44 upvote Intuitively, why does $\dfrac{a}{c} = \dfrac{1}{\dfrac{c}{a}}$? +10 18:42 upvote Understanding equivalence class, equivalence relation, partition +10 18:14 upvote First uncountable ordinal +10 08:27 upvote Intuition for dense sets. (Real analysis) +10 08:07 upvote Does $A^2 \cong B^2$ imply $A \cong B$ for rings? +10 06:10 upvote Number of onto functions +10 00:19 upvote Regular language or not? +10 00:03 upvote Can a knight visit every field on a chessboard? +10 00:03 upvote Intuition on group homomorphisms
100 2 days ago
 +30 22:03 3 events Does $A^2 \cong B^2$ imply $A \cong B$ for rings? +10 22:35 upvote Cardinal equality: $\;\left|\{0,1\}^{\Bbb N}\right|=\left|\{0,1,2,3\}^{\Bbb N}\right|$ +10 20:39 upvote Questions on “All Horse are the Same Color” Proof by Complete Induction +10 20:04 upvote A topological space is trivial iff every function to it is continuous +10 13:00 upvote What does $H(\kappa)$ mean? +10 08:23 upvote Prove that ${2^n-1\choose k}$ and ${2^n-k\choose k}$ ar always odd. +10 08:21 upvote Proving that ${k+x \choose 2k + 1}=-{k-x \choose 2k + 1}$ +10 03:39 upvote Does Pi contain all possible number combinations?
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