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visits member for 3 years, 4 months
seen Nov 4 '13 at 13:29

Jul
2
awarded  Curious
Oct
22
accepted Ring of $p$-adic integers $\mathbb Z_p$
Oct
22
accepted Discrete valuation on $p$-adic numbers
Oct
21
awarded  Editor
Oct
21
revised Discrete valuation on $p$-adic numbers
added 18 characters in body
Oct
21
comment Discrete valuation on $p$-adic numbers
Yes, of course. Sorry, I forgot, that $\mu_n(w)=v.$
Oct
21
asked Discrete valuation on $p$-adic numbers
Oct
15
asked Ring of $p$-adic integers $\mathbb Z_p$
Dec
2
comment Proving equation (with Hilbert symbol)
Thanks! It's clear now :-)
Dec
2
comment Proving equation (with Hilbert symbol)
I've computed: $(-ab,-c)=(-c,a)(-c,-b)=(-1,ac)(-c,-b)=(-1,ac)(-c,b)(-c,-1)=(-1,ac)(-1,bc)(-1,-c‌​)=(-1,-acbcc)$. But where is a mistake?
Dec
2
asked Proving equation (with Hilbert symbol)
Apr
23
accepted Existence of irreducible polynomials
Apr
22
comment Existence of irreducible polynomials
Ok, but it is not clear, that $f$ has only real roots. Maybe my question was a bit vague. All roots of the polynomial $f$ should be elements in $\mathbb R$.
Apr
22
awarded  Commentator
Apr
22
comment Existence of irreducible polynomials
Good idea. It would be great, if you have a source or a proof for it.
Apr
22
comment Existence of irreducible polynomials
Thanks for your answer.
Apr
22
asked Existence of irreducible polynomials
Mar
30
comment Realizing $S_n$ as a Galois group
You're right. There must exist a transposition, a $n-1$-cycle and the galois group have to be a transitive subgroup of $S_n$. Then the galois group is $S_n$. But I can't see, why a $n-1$-cycle exists.
Mar
30
asked Realizing $S_n$ as a Galois group
Jan
17
accepted Proof of inequality (mollifier)