| bio | website | nullteilerfrei.de |
|---|---|---|
| location | Germany | |
| age | 28 | |
| visits | member for | 1 year, 11 months |
| seen | 2 hours ago | |
| stats | profile views | 389 |
I'm a PhD student with research interests in Algebraic Geometry, Algebraic Complexity Theory and Computer Algebra, i.e. doing delicate algebra to come up with powerful algorithms.
|
Dec 28 |
comment |
How to find the number of homomorphisms of $\mathbb{Z}$ into $\mathbb{Z}$? You guys were right of course. Sorry for the confusion there. Fixed it. |
|
Dec 28 |
revised |
How to find the number of homomorphisms of $\mathbb{Z}$ into $\mathbb{Z}$? deleted 11 characters in body |
|
Dec 28 |
answered | How to find the number of homomorphisms of $\mathbb{Z}$ into $\mathbb{Z}$? |
|
Dec 16 |
answered | Algebra: Orthogonal Complement |
|
Dec 15 |
comment |
How many solutions are there to the equation $x + y + z + w = 17$? that's beautiful. |
|
Dec 15 |
revised |
How many solutions are there to the equation $x + y + z + w = 17$? beautified |
|
Dec 15 |
answered | How many solutions are there to the equation $x + y + z + w = 17$? |
|
Dec 13 |
comment |
How to calculate the maximum flow in this graph by the Edmonds-Karp algorithm? Oh and yea, the value of the maximum flow is 8. |
|
Dec 12 |
comment |
Complex Numbers Question @Some1: The point to my statement is that $f$ has real coefficients, but the second polynomial does not satisfy this condition. See I.J.Kennedy's answer. |
|
Dec 12 |
comment |
How to calculate the maximum flow in this graph by the Edmonds-Karp algorithm? I am not sure I understand your question. Do you know what a residual graph is? |
|
Dec 12 |
answered | Solving Linear Equation in One Unknown |
|
Dec 12 |
answered | Complex Numbers Question |
|
Dec 12 |
answered | How to calculate the maximum flow in this graph by the Edmonds-Karp algorithm? |
|
Dec 12 |
awarded | Analytical |
|
Dec 12 |
comment |
What does it mean to say a polynomial has an isolated singularity Let $R=k[x_1,\ldots,x_n]/f$ be the coordinate ring of $H=Z(f)$. The partial derivatives $g_i := \partial f/\partial x_i \in R$ are a minimal set of generators for the ideal of the isolated singularity. This follows because the maximal ideal of a singular point can not be generated by $n-1=\dim(H)$ elements, but it is generated by the $n$ elements $g_i$. |
|
Dec 12 |
answered | closed subschemes of projective space over a scheme |
|
Dec 2 |
answered | Euler characteristic in pullbacks |
|
Dec 2 |
comment |
Can the completion of a non-domain be a domain Your proof is completely correct. Just for fun and because it seems related, Theorem 7.9 from Eisenbud says that if $R$ is a local ring with maximal ideal $m$ that is a localization of a ring finitely generated over a field or $\mathbb{Z}$, then $\hat{R}$ has no nilpotent elements. |
|
Dec 2 |
answered | How is this problem called? |
|
Nov 5 |
comment |
Natural space to consider solution to polynomial equations $\mathbb{CP}^2$ has nice geometric properties: For instance, two lines always intersect in a point. In $\mathbb{C}^2$, you can have parallel lines that do not satisfy this condition. |