Jesko Hüttenhain
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6,431
79/100 score
 1d revised A is an antisymmetric matrix (of even size). B is another matrix such that $b_{i,j}=a_{i,j}+c$. Prove that |A|=|B| added 20 characters in body 1d comment A is an antisymmetric matrix (of even size). B is another matrix such that $b_{i,j}=a_{i,j}+c$. Prove that |A|=|B| Sorry, I thought you wanted a hint, because you said "Any hint?" ;). 1d answered A is an antisymmetric matrix (of even size). B is another matrix such that $b_{i,j}=a_{i,j}+c$. Prove that |A|=|B| Apr 26 revised What is the intuition behind a Euclidean function? added 6 characters in body Apr 26 comment Minimal free resolution of ideal generated by three homogeneous polynomials @user26857: Yes, good point. Do you have a reference? I am looking but can't find any so far. Apr 26 answered Minimal free resolution of ideal generated by three homogeneous polynomials Apr 26 answered Do finite morphisms preserve dimensions? Apr 24 comment Statement made by Borel on Linear Algebraic Groups page 79 Borel never claims that $K$ is a field extension of $k$, in fact you should rather think of $k$ as a field extension of $K$. Otherwise, the statement makes little sense. Apr 23 comment Irreducible variety Do you know that the image of a projective morphism is always closed? Apr 20 comment A is an antisymmetric matrix (of even size). B is another matrix such that $b_{i,j}=a_{i,j}+c$. Prove that |A|=|B| Eliminate all but the first $c$ in the first row by row operations, then eliminate all but the first $c$ in the first column by column operations and see what happens. If it's unclear, do this for a $4\times4$ example first. Next, use Laplace expansion for the first row and use the fact that the determinant of an odd-shaped antisymmetric matrix vanishes. Apr 20 revised Graph theory: creating surfaces edited tags Apr 20 revised Isomorphism of Quotient ring $\Bbb Q[x]/\langle x^3\rangle$ added 51 characters in body; edited title Apr 20 comment Why are there no $\mathbb{R}$-valued points on a complex curve? I think I had a similar problem before. Maybe the answer there is helpful to you as well. Apr 19 comment Localization Preserves Euclidean Domains Me too actually. I knew the statement but had never thought about the proof before =). Apr 19 revised Showing that the integers localized at a prime, p, is a Euclidean Domain added 38 characters in body Apr 19 comment Showing that the integers localized at a prime, p, is a Euclidean Domain I answered this over here in more generality. Apr 19 answered Localization of euclidean ring is euclidean? Apr 19 revised Localization Preserves Euclidean Domains added 19 characters in body Apr 19 comment Localization Preserves Euclidean Domains @rie: I changed the answer and corrected my mistake thanks to your insightful questions, indeed you have to make sure that $S$ is saturated for the argument to work. Apr 19 revised Localization Preserves Euclidean Domains added 1043 characters in body