115 reputation
5
bio website stackoverflow.com/users/…
location Chelmsford, United Kingdom
age 34
visits member for 3 years, 5 months
seen 2 days ago

I'm self-taught, with 3 years' experience as a web developer.

Currently looking for a C# ASP.NET MVC development position within Chelmsford or London. I've been out of work for quite a while, so if you have an opening for a junior position, I'd still like to know. I just want to get back to work.

john.hartley4 [AT] gmail [DOT] com


Oct
11
comment Why are these logical statements not deemed to be equivalent?
@ajotatxe Thanks for the comment. I'm inclined to agree, but I'd like some more feedback as the answer below has left me uncertain.
Oct
11
comment Why are these logical statements not deemed to be equivalent?
Sorry for the delayed response, and thanks for getting back to me. The book is Core Maths for Advanced Level, which is basically covering the core sections of the UK maths curriculum that 16-18 year olds would study, so it's by no means a book on pure logic.
Oct
11
comment Why are these logical statements not deemed to be equivalent?
I initially thought this, but it's only asking whether or not the point is on the line. It's not asking whether the equation the point was generated by is the same line.
Oct
11
awarded  Student
Oct
11
asked Why are these logical statements not deemed to be equivalent?
Sep
25
awarded  Commentator
Sep
25
accepted Without solving the equation, determine the nature of its roots: $x^2 + ax + a^2 = 0$
Sep
25
comment Without solving the equation, determine the nature of its roots: $x^2 + ax + a^2 = 0$
@MickG Contacting the authors is a good idea actually. I hadn't considered that. There is no qualifier ruling that a is not equal to zero, so it's a definite problem. This book is 15 years old, but I've never been able to find any published errata for it.
Sep
25
comment Without solving the equation, determine the nature of its roots: $x^2 + ax + a^2 = 0$
Thanks for the confirmation.
Sep
25
comment Without solving the equation, determine the nature of its roots: $x^2 + ax + a^2 = 0$
@taninamdar Thank you.
Sep
25
asked Without solving the equation, determine the nature of its roots: $x^2 + ax + a^2 = 0$
Feb
16
comment Active learning vs Passive learning in Math
That actually makes sense, thanks.
Feb
16
comment Active learning vs Passive learning in Math
Would you consider 'deliberate learning' to be the same as 'active learning'?
Nov
9
comment Logic - Translate a Math Statement
Oh, now it makes sense. Thanks a lot!
Nov
9
comment Logic - Translate a Math Statement
Doesn't "you must pay the daily fee unless you are a subscriber to the service" imply they are mutually exclusive, rather than inclusive?
Jul
23
awarded  Scholar
Jul
23
accepted Why can/do we multiply all terms of a divisor with polynomial long division?
Jul
23
comment Why can/do we multiply all terms of a divisor with polynomial long division?
Ah, now that makes complete sense. I think that was probably what I couldn't understand all along. I went back over the 48 / 28 problem and realised that I'd get 1 + (20 / 28). Writing that as (4 * 10 + 8) / (2 * 10 + 8) gives 2 - (8 / 28). Then I realised they are the same answer, expressed differently. I can't thank you enough for your help.
Jul
22
comment Why can/do we multiply all terms of a divisor with polynomial long division?
Thank you, too, for your answer and again, I'm sorry it's taken such a long time for me to reply. I like that you've given me a completely different way to view the problem.
Jul
22
comment Why can/do we multiply all terms of a divisor with polynomial long division?
I can see that it rebalances, but I'd like to understand how someone developed this method, assuming this was created for real numbers first, and realising it would work like this algebraically. The result is the same but the rebalancing by having a negative remainder seems very different to the method for real numbers (at least to me).