Just_a_fool
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 Apr 26 awarded Nice Question Mar 20 awarded Popular Question Jan 20 comment Equivalence between “a iff b” and “(a → b)^(b→a)” Thanks for your answer! I realise what I had in my mind would be more along the lines of $(a \implies b )\land(a\subset b)$. Jan 20 accepted Equivalence between “a iff b” and “(a → b)^(b→a)” Jan 20 comment Equivalence between “a iff b” and “(a → b)^(b→a)” Thank you for your answer! So "a if b" strictly means that " "a"must follow from "b" ". My mistake lied in thinking that "iff" does not yield this condition as a necessity. Thanks again. Jan 19 asked Equivalence between “a iff b” and “(a → b)^(b→a)” Dec 8 awarded Yearling Oct 18 awarded Popular Question May 12 accepted arccos and arcsin integral contradiction: May 12 comment arccos and arcsin integral contradiction: True, thanks! An added $pi/2$ on the LHS makes the expressions equal. So my mistake was in not considering that though the derivative of 2 functions may be very close, the original functions from which they were derived may have different constants of integration! May 12 asked arccos and arcsin integral contradiction: May 11 answered Number of times to roll a dice to get 4 or 2 Apr 18 comment Calculate $\sqrt{7+5\sqrt{2}}-\sqrt{3-2\sqrt{2}}$ Wow, its amazing that such an expression with roots within roots and roots of different degrees equates to 1... What type of math concerns itself with finding means to simplify such expressions? Mar 26 comment Given $2015$ points, show that it is possible to separate them such that $1007$ of them lie inside the circle @OscarCunningham What a great method man! It solves all the problems of the question extremely simply: your circle will never "hit" 2 points at once, as for that to happen you would have to be along a perpendicular bisector; much less about hitting more than 2 dots simultaneously (e.g. 3 dots), as that wold only occur if your new point were on the intersection of 2 or more bisectors. You just keep growing untill you hit 1007 :). OP, this guy has fully answered your question, and only in three lines! Mar 26 answered Given $2015$ points, show that it is possible to separate them such that $1007$ of them lie inside the circle Mar 14 suggested rejected edit on When, how & who first gave this calculation of $\pi$ Mar 2 answered prove there is no smallest positive rational number Feb 16 comment What is wrong with this “inference” about partitions? Oh... I just realized I stated A>B, C>D and A>C and concluded A-C>B-D Feb 16 comment What is wrong with this “inference” about partitions? Thanks for your reply. Though, I have, in a little thing I'm trying to write, precisely done all of what you stated, lol. The problem is, this argument allows me to a develop a lower bound for p(n), namely 1.7^n, which is incorrect. Feb 16 asked What is wrong with this “inference” about partitions?