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1d
revised parabolic function, sth deal with period
latex added
Sep
17
comment what would be the answer
hint:3 number's average is 14, so if one side of the equation has 14, the other side must have 3 in denominator. Argument (2) if we are multiplying the side which has 3 in denominator to get rid of 3, then we must multiply the side that has 14 by 3
Sep
17
revised what would be the answer
latex added
Sep
17
answered Birdwatching question
Sep
14
comment Need explanation how we got right hand side of expression from the left hand side
$\large \frac{n(n-1)...(n-(r-1))}{r!}=\frac{n(n-1)...(n-(r-1))}{r!}.\frac{(n-r)!}{(n-r)!‌​}=\frac{n!}{r!(n-r)!}$
Sep
14
revised Finding dimensions using quadratic formula
answer corrected
Sep
14
answered Finding dimensions using quadratic formula
Sep
14
answered Problem Solving quadratics
Sep
14
comment Problem Solving quadratics
If $a$ and $b$ are the sides of paddock, then $2(a+b)=600$ and $a \times b=21600$
Sep
14
comment How to solve this equation ? nC30 = nC20
$^nC_{30} \ = \ ^n C_{n-30}$, now equate this with $^nC_{20} $, we get $n-30=20$
Sep
14
comment How to find a Boolean expression for a combinational logic circuit?
I am not sure but I think you will have to simplify this to get the required expression:"$Z=-(-(A \wedge B) \vee -(A \wedge B) \wedge -(B \wedge C)) \wedge (-(A \wedge B) \wedge -(B \vee C))$"
Sep
14
comment How to find a Boolean expression for a combinational logic circuit?
@CarlosMendez, pls see the edited answer
Sep
14
revised How to find a Boolean expression for a combinational logic circuit?
improved answer
Sep
14
comment How to find a Boolean expression for a combinational logic circuit?
you will have to check for all the different input combinations
Sep
14
answered How to find a Boolean expression for a combinational logic circuit?
Sep
14
comment Is the empty set a member of itself
math.stackexchange.com/questions/302064/…
Sep
13
comment Analysis of the function $y=x^{\frac{1}{x}}$
yes, you are right
Sep
13
comment Analysis of the function $y=x^{\frac{1}{x}}$
if $x=-3/2$ then $y=\frac{1}{(\sqrt{-3/2})^3}$
Sep
13
comment Analysis of the function $y=x^{\frac{1}{x}}$
@Dave, for both $-3/2$ and $-1.5$, excel is not giving any answer
Sep
13
asked Analysis of the function $y=x^{\frac{1}{x}}$