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Nov
17
awarded  Popular Question
Nov
10
comment Circles - Radius question
If you like the diagram keep it, else delete it.
Nov
10
revised Circles - Radius question
Improved answer by supplying a diagram
Nov
6
comment Trigonometric Word Problem Law of Sine and Cosine
first, law of sine then Pythagorous theorem
Nov
3
comment Large round brackets in equation
$ n \choose r $ is another way of representings $^{n} C_r$
Oct
31
comment Finding the slope of X
formula for slope of a line is $m=\frac{y_2-y_1}{x_2-x_1}$,
Oct
27
comment Solving speed problem
at time $t_0$ the front of the car is level with the back of the caravan; at time $t_1$ the back of the car is level with the front of the 4WD; from $t_0$ to $t_1$ the car has to travel $(13 + 5)$ m and considering the caravan to be stationary for calculation purpose then the car is travelling at a speed of $(100-64)$ km/h, now we know the speed of the car and the distance it has to travel.
Oct
18
comment Some help with sin and cos
For first part $a=\sin^2\pi/2$, $b=\cos^2\pi/2$ ; $\Large\frac{1-\frac{a}{b}}{1+\frac{a}{b}}=\frac{\frac{b-a}{b}}{\frac{b+a}{b}}= \frac{b-a}{b+a}$ use $\sin^2\theta+\cos^2\theta=1$
Oct
17
comment A problem regarding table decorations
if all 3 must be of different color then answer is minimum of r,g,b; if color does not matter then answer is integer part of (r+g+b)/3
Sep
30
awarded  Explainer
Sep
27
comment how to solve liner equations with decimal values like 2n=0.58(12 - n)
$29(12-n)=30(12-n)-(12-n)$, is one of the tricks to avoid 29
Sep
17
answered Birdwatching question
Sep
14
comment Need explanation how we got right hand side of expression from the left hand side
$\large \frac{n(n-1)...(n-(r-1))}{r!}=\frac{n(n-1)...(n-(r-1))}{r!}.\frac{(n-r)!}{(n-r)!‌​}=\frac{n!}{r!(n-r)!}$
Sep
14
revised Finding dimensions using quadratic formula
answer corrected
Sep
14
answered Finding dimensions using quadratic formula
Sep
14
answered Problem Solving quadratics
Sep
14
comment Problem Solving quadratics
If $a$ and $b$ are the sides of paddock, then $2(a+b)=600$ and $a \times b=21600$
Sep
14
comment How to find a Boolean expression for a combinational logic circuit?
I am not sure but I think you will have to simplify this to get the required expression:"$Z=-(-(A \wedge B) \vee -(A \wedge B) \wedge -(B \wedge C)) \wedge (-(A \wedge B) \wedge -(B \vee C))$"
Sep
14
comment How to find a Boolean expression for a combinational logic circuit?
@CarlosMendez, pls see the edited answer
Sep
14
revised How to find a Boolean expression for a combinational logic circuit?
improved answer