228 reputation
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location San Jose, CA
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visits member for 3 years, 2 months
seen Jul 20 at 5:13

Jun
28
awarded  Notable Question
May
15
awarded  Caucus
Apr
28
comment Interesting question about irrational numbers
Since $7-a-b$ is an integer, $2\sqrt{10}-2\sqrt{ab}$ must also be an integer, and $\sqrt{10}$ is irrational. That should help.
Apr
28
revised Domain of a Relation from A to B
improved formatting, summarize question
Apr
28
asked Domain of a Relation from A to B
Apr
28
comment Elementary explanation of determinant
I think the best way would be to show example of 2x2, 3x3 systems where the determinant shows up in the solution. Could add that the determinant is a function that takes as input a matrix and yields a number. But have they covered the concept of functions?
Feb
25
awarded  Popular Question
Jan
11
comment $(p \land q)\implies(p \lor q)$, how to make a truth table with $p$ twice?
Break it up: First the two usual columns: $p$, $q$. Then build the $p \land q$, and the $p \lor q$ columns from the values in the first two columns. Then build the final column based on columns 3 and 4.
Nov
17
comment is Pi a static number?
@BrianM.Scott: Ok, You are correct about the second para. I guess I was just too shocked by the rest of the "question" to see that...
Nov
17
comment is Pi a static number?
@BrianM.Scott: Most?
Nov
17
comment is Pi a static number?
Huh?...................
Nov
17
revised Exponents in Odd and Even Functions
case of f odd, g even
Nov
17
revised Exponents in Odd and Even Functions
added proff
Nov
17
answered Exponents in Odd and Even Functions
Nov
16
awarded  Yearling
Nov
15
answered Are trig identities commutative?
Nov
15
answered What's the solution to this system of equation?
Nov
6
comment Simple algebra question…exponents?
Well whoever told you it was not 1 was wrong.
Nov
6
comment Simple algebra question…exponents?
I think you understanding is incorrect. That is clearly 1, ($b \ne 0$). The only way that is $b^8$ is the question is $\frac{b^4}{b^{-4}}$
Oct
31
comment Proof by Induction: $\sum_0^nx^i=(1-x^{n+1})/(1-x)$
The left hand side for $n=1$ expands to $x^0+x^1 = 1 + x, x \ne 0$