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visits member for 3 years, 2 months
seen Jul 19 at 18:05

Jul
2
awarded  Curious
Jun
10
comment Approximation of $C^\alpha(T^2)$ in $L^1$ by a $C^k$ function
Yes. Here I want a $C^k$, $k<\infty$ approximation, also I want the approximation in $L^1$. Given these milder restrictions (as opposed to $C^\infty$ and approximation in $L^\infty$) I wonder what is the best bound one can get for $\|f_\epsilon\|_{C^k}$.
Jun
9
comment Approximation of $C^\alpha(T^2)$ in $L^1$ by a $C^k$ function
Could you show me the calculation?
Jun
5
asked Approximation of $C^\alpha(T^2)$ in $L^1$ by a $C^k$ function
Jul
7
accepted The boundedness of $x^k e^{-|x|}$
Jul
4
comment The boundedness of $x^k e^{-|x|}$
Thanks @Ethan .
Jul
4
asked The boundedness of $x^k e^{-|x|}$
Jul
3
asked approximate Fourier transform
May
23
awarded  Yearling
May
9
awarded  Caucus
Apr
16
comment Bernoulli shift on $S^\mathbb{Z}$
First prove it for cylinders. Then prove it for finite unions of cylinders. I think then you can use an approximation argument: approximate (in symmetric difference) an arbitrary measurable set with finite union of cylinders.
Apr
16
comment Nonconstant linear functional on a topological vector space is an open mapping
You are assuming $f$ is continuous, which is not part of Rudin's statement.
Apr
16
revised Nonconstant linear functional on a topological vector space is an open mapping
added 21 characters in body
Apr
16
revised Nonconstant linear functional on a topological vector space is an open mapping
Fixed some typos.
Apr
16
suggested suggested edit on Nonconstant linear functional on a topological vector space is an open mapping
Apr
16
awarded  Benefactor
Apr
15
revised Nonconstant linear functional on a topological vector space is an open mapping
added 7 characters in body; edited title
Apr
13
accepted Weakest hypothesis for integration by parts
Apr
13
comment Weakest hypothesis for integration by parts
Can you provide the proof of $G$ being absolutely continuous? Also what assumptions do you need to integrate the right side of equation (2)?
Apr
12
comment Why is this function Lipschitz?
$f(x)=x^{1/2}$ on $[0,1]$ satisfies your inequality with $C=1/2$, but it's not Lipschitz.