Dec
18
comment Prove that $a^ab^bc^c\ge (abc)^{(a+b+c)/{3}}$
That was not intended as a help for you. you mentioned that the question was already posed but did not supply a link.
Dec
18
comment Prove that $a^ab^bc^c\ge (abc)^{(a+b+c)/{3}}$
math.stackexchange.com/questions/109783/…
Dec
10
comment Dynamic programming:Making a Change
no, this is not a dynamic programming approach.
Dec
9
comment Dynamic programming:Making a Change
so which coin values do you have and how many of them? Why don't you check five one-dollar and one five-dollar coins?
Dec
9
comment Dynamic programming:Making a Change
I can't catch your idea. Can you explain more? Maybe there will be a more instructive example. You did not mention which types of coin denomination you have. why don't you check five one-dollar and oen five-dollar notes?
Dec
9
comment Binary operation commutative, associative, and distributive over multiplication
what have you tried?
Nov
30
comment What is the value of $a+b+c$?
You should post a new question if you have another question.
Nov
30
comment What is the value of $a+b+c$?
Can you show this "some algebra" and calculate the solution?
Nov
30
comment What is the value of $a+b+c$?
Can you calculate the solution?
Nov
25
comment Why can ALL quadratic equations be solved by the quadratic formula?
$x-\alpha = x-\beta = 0$ would imply $\alpha=\beta=0$. Your proof needs the theorem from vieta. I can't see how you get to the result by adding equations 2 and 3 as you stated in the text. Sorry, but the whole proof is rather complicated and rather boring.
Nov
24
comment How to find the sum of this : $\sqrt{1+\frac{1}{1^2}+\frac{1}{2^2}}+ \sqrt{1+\frac{1}{2^2}+\frac{1}{3^2}}+\sqrt{1+\frac{1}{3^2}+\frac{1}{4^2}}+…$
@user158108: $$n^2 \cdot (n+1)^2 + n^2 + (n+1)^2=n^4+2 n^3+3 n^2+2 n+1$$ But polynomial equations of type $$x^4+ax^3+bx^2+ax+1=0$$ can be transformed to $$(x^4+1)+ax(x^2+1)+bx=0$$ and further to $$x^2((x+\frac{1}{x})^2-2)+a(x+\frac{1}{x})+c)=0$$ Now the substitution $$y=x+\frac{1}{x}$$ can be used.
Nov
24
comment An interesting table of Prime Generating polynomials similar to $n^2+n+41$?
To me it seems that these are at least 5 questions.
Nov
24
comment Prove that $F(1) + F(3) + F(5) + … + F(2n-1) = F(2n)$
and you start with which $n$? For $n=1$ you get $0=f(1)=f(2)=?$
Nov
24
comment Prove that $F(1) + F(3) + F(5) + … + F(2n-1) = F(2n)$
Why do you use two different notations for the numbers? Either $f(n)$ of $F(n)$. Then numbers are $0,1,1,2,3,5,\ldots$. So if $f(5)=5$ then $f(1)=1, f(3)=2$.
Nov
21
comment $P(x+2)=2x^3-4x^2+2x+3$. Find the remainder of $\dfrac{P(x)}{(x-3)}$
What does $P(u)=2(x-2)^3-4(x-2)^2+2(x-2)+3$ mean? Do you want the remainder of $P(x)/x-3=\frac{P(x)}{x}-3$ or of $P(x)/(x-3)=\frac{P(x)}{x-3}$
Nov
19
comment What is indefinite integral actually - $\int f(x)dx$ or $\int_a^x f(t)dt$?
How is a function $F(x)=\int_0^xf(t)dt$ connected with the antiderivates? It is an antiderivate of $f$ if $f$ is continous, so $F'(x)=(\int_0^xf(t)dt)'=f(x)$. To see this one has to proof that $\lim_{h \to 0} \frac{F(x+h)-F(x)}{h}=\lim_{h \to 0} \frac{\int_0^{x+h}f(t)dt-\int_0^xf(t)dt}{h}=\lim_{h \to 0} \frac{\int_x^{x+h}f(t)dt}{h}$ is equal to $f(x)$
Nov
19
comment What is indefinite integral actually - $\int f(x)dx$ or $\int_a^x f(t)dt$?
For example select $a=0$ and $f(t)=t^2$ and therefore $F(x)=\int_0^x t^2 dt$. So for $x=3$ the function value $F(3)$ is the definite integral $\int_0^3 t^2 dt$, which is $9$, for $x=4$ the function value $F(4)$ is the definite integral $\int_0^4 t^2 dt$, which is $64/3$
Nov
19
comment What is indefinite integral actually - $\int f(x)dx$ or $\int_a^x f(t)dt$?
you are right, thank you
Nov
19
comment What is indefinite integral actually - $\int f(x)dx$ or $\int_a^x f(t)dt$?
Does your book (which book?) really say it is a family of equations? I think it should say it is a family of functions.
Nov
17
comment Union of Two Rectangles is the Disjoint Union of at most $6$ Rectangles
Can you show an example for $X = \mathbb R \times \mathbb R$ where 6 rectangles are needed?