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Jan
3
reviewed Reject Modulo of a negative number
Jan
3
reviewed Approve Number of Infinities in complex numbers
Jan
3
reviewed Reject Number of $0$ in great number
Jan
3
comment questions about probabilistic primality test
Which online Rabin-Miller test do you use? Can you provide the link?
Jan
3
comment How to show result in terms of $\pi$ in Mathcad?
@Rory Daulton: No, it is absolutely on topic to pose a question about Mathcad. If it is a question about Mathcad it does not make sense to change it in a question about anything else. I think the post is about symbolic calculation in Matchcad.
Jan
3
reviewed Approve Question of difficult matrix problem, minimum number of times
Jan
3
revised How does (wikipedia's axiomatization of) intuitionistic logic prove $p \rightarrow p$?
line numbers instead of bullets, makes iteasier to reference
Jan
2
revised Is $1234567891011121314151617181920212223…$ an integer?
removed the invalid "the number" in title
Jan
2
comment Is $1234567891011121314151617181920212223…$ an integer?
I modified the post you referenced becuase it is simply wrong to calll $123\ldots$ a number. Your question title is not posed wll, too. I changed your question tile too, because it contains the invalid assumption that this is a number.
Jan
2
revised The $2013$th digit of $1234567891011213141516\ldots$
changed "number" to "string" becuase this is not a number
Jan
2
comment The following is unclear to me:($f$ is the identical function) the inverse of $f: X\to X$ is not continuous(if the second space isnt discrete)
The OP contains its (valid) definition of a continous function, so you should write an answer according to this definition and not simply reproduce a standard proof
Jan
1
comment Show $1+x+(x^2/2!)+ \cdots + (x^n/n!)=0$ has no rational solutions for all $n>1$.
you should withdraw the acceptance of this answer. It does not make sense to accept an unvalid answer: The question is now a question with an accepted answer and so nobody who looks for open questions to answer will find it.
Jan
1
comment Show $1+x+(x^2/2!)+ \cdots + (x^n/n!)=0$ has no rational solutions for all $n>1$.
How does the solution that you accepted help you. It stopped there where you already were ($q=\pm 1, p \mid n!$)?
Jan
1
reviewed Approve What is a function?
Jan
1
comment Prime Number Sieve using LCM Function
The $b_n$ are actually two independent sequences: $$\\ b_{n}=b_{n-1}+\text{lcm}(2n-1,b_{n-1}), n \ge 2, b_1 =2, \text{former even indexes} \\ b_{n}=b_{n-1}+\text{lcm}(2n-2,b_{n-1}), n \ge 2, b_1=2, \text{former odd indexes} $$ a similar sequence: $$b_n = b_{n-1} + \text{lcm}(n,b_{n-1}), n\ge 2, b_1=1$$ oeis.org/A135504 , oeis.org/A217663
Jan
1
revised Prime Number Sieve using LCM Function
formatted maxima code
Dec
31
comment Counterexample to disprove that $P(A-B) = P(A) - P(B)$?
It is always $$P(A-B) \ne P(A) - P(B)$$ because the lhs contains the empty set and the rhs does not.
Dec
31
comment A generalized derivative
I think it should be $\alpha f(x)^{\alpha-1}\cdot f'(x)\left|\right._{x=x_0}$
Dec
31
revised How many zeroes would be there at the end of $11^{(5!)!}-1$?
added 30 characters in body; edited tags
Dec
31
revised How many combinations can a group of n people form?
subsets with one elemnt must be excluded