miracle173
Reputation
3,287
Next privilege 5,000 Rep.
Approve tag wiki edits
 Jan3 reviewed Reject Number of factors of a big number Jan3 reviewed Reject Modulo of a negative number Jan3 reviewed Approve Number of factors of a big number Jan3 reviewed Reject Modulo of a negative number Jan3 reviewed Approve Number of Infinities in complex numbers Jan3 reviewed Reject Number of $0$ in great number Jan3 comment questions about probabilistic primality test Which online Rabin-Miller test do you use? Can you provide the link? Jan3 comment How to show result in terms of $\pi$ in Mathcad? @Rory Daulton: No, it is absolutely on topic to pose a question about Mathcad. If it is a question about Mathcad it does not make sense to change it in a question about anything else. I think the post is about symbolic calculation in Matchcad. Jan3 reviewed Approve Question of difficult matrix problem, minimum number of times Jan3 revised How does (wikipedia's axiomatization of) intuitionistic logic prove $p \rightarrow p$? line numbers instead of bullets, makes iteasier to reference Jan2 revised Is $1234567891011121314151617181920212223…$ an integer? removed the invalid "the number" in title Jan2 comment Is $1234567891011121314151617181920212223…$ an integer? I modified the post you referenced becuase it is simply wrong to calll $123\ldots$ a number. Your question title is not posed wll, too. I changed your question tile too, because it contains the invalid assumption that this is a number. Jan2 revised The $2013$th digit of $1234567891011213141516\ldots$ changed "number" to "string" becuase this is not a number Jan2 comment The following is unclear to me:($f$ is the identical function) the inverse of $f: X\to X$ is not continuous(if the second space isnt discrete) The OP contains its (valid) definition of a continous function, so you should write an answer according to this definition and not simply reproduce a standard proof Jan1 comment Show $1+x+(x^2/2!)+ \cdots + (x^n/n!)=0$ has no rational solutions for all $n>1$. you should withdraw the acceptance of this answer. It does not make sense to accept an unvalid answer: The question is now a question with an accepted answer and so nobody who looks for open questions to answer will find it. Jan1 comment Show $1+x+(x^2/2!)+ \cdots + (x^n/n!)=0$ has no rational solutions for all $n>1$. How does the solution that you accepted help you. It stopped there where you already were ($q=\pm 1, p \mid n!$)? Jan1 reviewed Approve What is a function? Jan1 comment Prime Number Sieve using LCM Function The $b_n$ are actually two independent sequences: $$\\ b_{n}=b_{n-1}+\text{lcm}(2n-1,b_{n-1}), n \ge 2, b_1 =2, \text{former even indexes} \\ b_{n}=b_{n-1}+\text{lcm}(2n-2,b_{n-1}), n \ge 2, b_1=2, \text{former odd indexes}$$ a similar sequence: $$b_n = b_{n-1} + \text{lcm}(n,b_{n-1}), n\ge 2, b_1=1$$ oeis.org/A135504 , oeis.org/A217663 Jan1 revised Prime Number Sieve using LCM Function formatted maxima code Dec31 comment Counterexample to disprove that $P(A-B) = P(A) - P(B)$? It is always $$P(A-B) \ne P(A) - P(B)$$ because the lhs contains the empty set and the rhs does not.