May
24
comment A question about the minesweeper game
@ajotatxe: you are right
May
24
comment A question about the minesweeper game
For the $n*1$ board the maximum is $\lceil \frac{n}{2} \rceil$.
May
24
comment A question about the minesweeper game
Of course the maximum exists. If you add a bomb to the board the sum will be changed by a value in $\{-8,\ldots,8\}$. So the maximum is less or equal than $8*\text{lengh}*\text{width}$.
May
22
awarded  Yearling
May
14
revised How to find the closure of the following set?
removing some tex tags that where outside of tex
May
14
comment Visually stunning math concepts which are easy to explain
I think one understands nothing but will believe everything if one looks at this moving picture. That really is good "1st April" joke.
May
14
revised To solve $2\cdot(5^y)-7^x=1$
tex symbol
May
10
comment Would like to know which version of inductive formula is better
This question is about syntax and does not depend on any interpretation V. So it is not specific to a 4 valued logic.
May
10
reviewed Approve suggested edit on locate any bifurcation in the $2D$ system?
May
7
reviewed Approve suggested edit on Functions Question
May
3
reviewed Approve suggested edit on What is the subset of the letters in the word 'numbers'
May
2
answered Algorithms for factoring multivariate polynomials
May
1
revised How to do epsilon delta proof of continuity
changing the proof for the limit of the root
May
1
revised How to do epsilon delta proof of continuity
changing the proof for the limit of the root
May
1
answered How to do epsilon delta proof of continuity
Apr
17
comment Calculate the last digit of $3^{347}$
$$(3^5)^{69} *3^2 =3^{69} *3^2$$
Apr
8
awarded  Custodian
Apr
8
reviewed Approve suggested edit on If $f \in C^\infty$, and $f$ is nonnegative and integrable in $\mathbb{R}$, can I say that $f^\prime$ is integrable?
Apr
3
comment How can a piece of A4 paper be folded in exactly three equal parts?
1) With this method one can fold a letter an arbitrary number of times (if one does not reach physical limits ). So if one wants to fold it in 5 equal parts one first folds it in $2^3=8$ equal parts and the folds along the line through the top corner and the 5th mark. 2) One must use the second dimensions. When folding only parallel to one side one cannot fold into 3 equal parts. It is not possible to partition an interval $[0,1]$ in three equal parts by bisecting . The points that you can construct this way are $0,1$ and points of the form $\frac{n}{2^k}$.
Mar
21
comment What is the probability that the “smartest” of them has IQ score above 120?
"the smartest of them has IQ score above 120" is the opposite of "all of them have IQ score below 120"