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Oct
21
comment Why decimal expansion of $e$ has two copies of $1828$
The comment of joriki is making me paranoid. Jasper is onto something.
Oct
20
awarded  Popular Question
Oct
19
comment Fourier Series: Integral of a Sum or Sum of Integrals?
@MattN. Badges are all I live for.
Oct
17
comment Fourier Series: Integral of a Sum or Sum of Integrals?
@MattN. I don't think so. This is more PDE-like things.
Oct
14
comment Fourier Series: Integral of a Sum or Sum of Integrals?
This does not seem to answer the question.
Oct
14
answered Fourier Series: Integral of a Sum or Sum of Integrals?
Oct
2
asked On the regularity of the Laplace equations and tensor products and such
Sep
21
awarded  Custodian
Sep
9
comment Tablet for reading textbooks and writing math by hand?
Also, your drawings are pretty damn good if you don't have a stylus... Also with.
Sep
9
comment Tablet for reading textbooks and writing math by hand?
As for the "taking with you". You can put the files in a dropbox folder and the iPad client synchronizes them when you need.
Sep
5
comment Completeness of BMO without duality to $H^1$
That's what I say. In the quotient space. Maybe a bit "strange", but all the constants are now in the class $[0]$. Whatever, just get rid of the average and work with those functions.
Sep
4
comment Completeness of BMO without duality to $H^1$
@AlexanderAmenta I'm not sure what the problem is. As I am a bit ill al the moment, I still have tried to add some information :-). The idea is that it can only be a Banach space if we have a full norm. That means we should divide out that constants. In practice this means that taking the quotient gives us the normal BMO-norm for non-constants and the constant itself for constants. So, you are fine by just considering functions with average 0. Then no worrying about equivalence classes.
Sep
4
revised Completeness of BMO without duality to $H^1$
added 3032 characters in body
Sep
4
comment Completeness of BMO without duality to $H^1$
In these things seminorms suck. Consider equivalence classes of functions that are the same up to an additive constant.
Sep
3
comment Completeness of BMO without duality to $H^1$
@AlexanderAmenta But you get it for every compact set, I don't understand the question.
Aug
18
comment Outer measure of a union of 2 subsets of disjoint measurable sets of real numbers.
I like Byron's edit.
Aug
15
awarded  Enlightened
Aug
15
awarded  Nice Answer
Aug
12
awarded  Yearling
Aug
5
awarded  Self-Learner