7,264 reputation
12554
bio website fa.its.tudelft.nl/~teuwen
location Delft, Netherlands
age 28
visits member for 3 years, 11 months
seen Aug 5 '13 at 10:51

About me

I'm a PhD candidate in analysis (harmonic analysis). I have a Master of Science degree in mathematics (analysis).

I am interested in many topics in analysis, but in particular: harmonic analysis, functional analysis, operator theory and special functions.

My email address is jonasteuwen@gmail.com.

I would appreciate it if you would correct my spelling and grammatical errors.


Me elsewhere


Sep
9
comment Tablet for reading textbooks and writing math by hand?
As for the "taking with you". You can put the files in a dropbox folder and the iPad client synchronizes them when you need.
Sep
5
comment Completeness of BMO without duality to $H^1$
That's what I say. In the quotient space. Maybe a bit "strange", but all the constants are now in the class $[0]$. Whatever, just get rid of the average and work with those functions.
Sep
4
comment Completeness of BMO without duality to $H^1$
@AlexanderAmenta I'm not sure what the problem is. As I am a bit ill al the moment, I still have tried to add some information :-). The idea is that it can only be a Banach space if we have a full norm. That means we should divide out that constants. In practice this means that taking the quotient gives us the normal BMO-norm for non-constants and the constant itself for constants. So, you are fine by just considering functions with average 0. Then no worrying about equivalence classes.
Sep
4
revised Completeness of BMO without duality to $H^1$
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Sep
4
comment Completeness of BMO without duality to $H^1$
In these things seminorms suck. Consider equivalence classes of functions that are the same up to an additive constant.
Sep
3
comment Completeness of BMO without duality to $H^1$
@AlexanderAmenta But you get it for every compact set, I don't understand the question.
Aug
18
comment Outer measure of a union of 2 subsets of disjoint measurable sets of real numbers.
I like Byron's edit.
Aug
15
awarded  Enlightened
Aug
15
awarded  Nice Answer
Aug
12
awarded  Yearling
Aug
5
awarded  Self-Learner
Jul
30
comment Example of application of the Uniform Boundedness Principle
Nice proof, but indeed: it can be done easier. However, you can also use BS to prove there exists a function such that the Fourier series diverges.
Jul
19
comment Advantage of accepting non-measurable sets
@MichaelGreinecker The second part about probability theory seems to suggest to me that we are doing it wrong if we need to consider all the other events which are not even there. Do you know free probability? That takes the random variables as primitives.
Jul
19
comment A question about a proof of a weak form of Hilbert's Nullstellensatz
Thanks for the link. I always wanted to learn more about commutative algebra and your writing style suits me very well (as in that you don't make it sound more fancy than it actually is for example).
Jul
4
comment Drying blood - an algorithm for calculating the geometry of blood stains
@Rahul Maybe for pure mathematics, but it can surely be a good question for applied (and computational) mathematics where things are not so clearly defined. Maybe this is not the right forum?
Jul
1
comment A lemma about extension of function
I think the statement is like: if you take a point on the boundary, we do have an extension of $f$ there which is $C^m$ as well.
Jul
1
comment A lemma about extension of function
@Alex Yes, I agree. But I was wondering, that if you can do that, what would it look like... AC is quite non-constructive. Perhaps if it works, it will work for a very large class of domains, but maybe in general, the domains are not so bad and you can have a (reasonably) explicit construction.
Jul
1
comment A lemma about extension of function
@Alex: That is quite a cool proof. But, what is actually going on there?
Jul
1
revised A lemma about extension of function
added 1460 characters in body
Jul
1
answered A lemma about extension of function