| bio | website | |
|---|---|---|
| location | ||
| age | 21 | |
| visits | member for | 2 years |
| seen | Mar 16 at 13:51 | |
| stats | profile views | 22 |
I'm an experienced C++ programmer. B.Sc. student in pure mathematics department in Tel-Aviv university.
Some of my programming projects are:
- Stannum.Printf — Formats faster than you type.
- uniqoda — Input Unicode characters by name.
- UTF-8 everywhere — It's UTF-8 and it should be everywhere!
StackOverflow philosophy: Up vote those and only those whose reputation is lower than yours.
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Dec 24 |
awarded | Critic |
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Dec 22 |
revised |
Zeros of Fourier transform of a function in $C[-1,1]$ grammar |
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Dec 22 |
revised |
Zeros of Fourier transform of a function in $C[-1,1]$ deleted 16 characters in body |
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Dec 22 |
revised |
Zeros of Fourier transform of a function in $C[-1,1]$ edited body |
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Dec 22 |
awarded | Scholar |
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Dec 22 |
comment |
Zeros of Fourier transform of a function in $C[-1,1]$ +1 for solving this in an interesting way :). See the "intended" solution posted by me. |
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Dec 22 |
accepted | Zeros of Fourier transform of a function in $C[-1,1]$ |
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Dec 22 |
answered | Zeros of Fourier transform of a function in $C[-1,1]$ |
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Dec 20 |
comment |
Zeros of Fourier transform of a function in $C[-1,1]$ OK. Actually what I said (except that for ratio I meant product) is equivalent to the question of whether $\Im h(z)$ may grow faster than $\Re h(z)$. I'll see if I can apply Cauchy-Riemann equations. Does it even sound correct? |
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Dec 20 |
comment |
Zeros of Fourier transform of a function in $C[-1,1]$ Everything is fine except for the missing part ... Except for the intuition that near essential singularities the function goes crazy enough, I cannot see why $\frac{h(z)}{z}$ cannot maintain an almost imaginary ratio with $\frac{z}{|z|}$ so that its image would still be almost all of $\mathbb{C}$ yet the real part of the product would remain close to zero. |
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Dec 19 |
awarded | Teacher |
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Dec 19 |
revised |
Constant analytic function inside the disk format math. |
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Dec 19 |
suggested | suggested edit on Constant analytic function inside the disk |
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Dec 18 |
revised |
Zeros of Fourier transform of a function in $C[-1,1]$ added 580 characters in body |
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Dec 17 |
revised |
Zeros of Fourier transform of a function in $C[-1,1]$ added 1 characters in body |
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Dec 17 |
revised |
Zeros of Fourier transform of a function in $C[-1,1]$ added 5 characters in body |
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Dec 17 |
revised |
Zeros of Fourier transform of a function in $C[-1,1]$ edited title |
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Dec 17 |
asked | Zeros of Fourier transform of a function in $C[-1,1]$ |
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Dec 12 |
awarded | Editor |
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Dec 12 |
comment |
problems about normal subgroups and the index Please check the wording of the first item. You first define $K$ and then talk about $N$, and I think it should be $([G:N],|H|) = 1$. |