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Sep
30
awarded  Explainer
Sep
1
comment Principles of Mathematical Analysis, Dedekind Cuts, Multiplicative Inverse
Since $p < 1$, there exists an integer $n$ great enough to satisfy $p < 1 - (n + 1)^{-1}$. Then for each $m$ greater than $n$ inequality (1) holds.
Aug
21
awarded  Informed
Jun
5
awarded  Nice Answer
May
18
awarded  Yearling
Dec
8
revised Upper bound for norm of Hilbert space operator
improved formating
Dec
8
answered Upper bound for norm of Hilbert space operator
Nov
8
answered Why is it that the vector space of all derivations has the basis $\partial/\partial{x_1} \ldots \partial/\partial{x_n}$?
Nov
6
answered Why is this true:$ \nabla \cdot (\vec V \otimes \vec V)=(\vec V\cdot \nabla ) \vec V +\vec V(\nabla\cdot \vec V) \;\;? $
Jul
19
revised Suppose $xyz=8$, try to prove that $\sqrt{\frac{1}{1+x}}+\sqrt{\frac{1}{1+y}}+\sqrt{\frac{1}{1+z}}<2$
Replaced the initial wrong proof.
Jul
18
answered Suppose $xyz=8$, try to prove that $\sqrt{\frac{1}{1+x}}+\sqrt{\frac{1}{1+y}}+\sqrt{\frac{1}{1+z}}<2$
Jul
10
comment Proving $\frac{a^4}{b^3} +\frac{b^4}{c^3} +\frac{c^4}{a^3} \ge 3$
There was a typo. I corrected it. Thanks.
Jul
10
revised Proving $\frac{a^4}{b^3} +\frac{b^4}{c^3} +\frac{c^4}{a^3} \ge 3$
Corrected typo
Jul
10
revised Proving $\frac{a^4}{b^3} +\frac{b^4}{c^3} +\frac{c^4}{a^3} \ge 3$
Improved formatting
Jul
10
answered Proving $\frac{a^4}{b^3} +\frac{b^4}{c^3} +\frac{c^4}{a^3} \ge 3$
Jul
9
comment Proving $\frac{a^4}{b^3} +\frac{b^4}{c^3} +\frac{c^4}{a^3} \ge 3$
Can you explain me how you deduced $\min_{a^5+b^5+c^5=3}\frac{a^4}{b^3} +\frac{b^4}{c^3} +\frac{c^4}{a^3} \ge \max_{a^5+b^5+c^5=3}3(abc)^{\frac 1 3}$?
Jun
18
answered Please the Inequality in the proof of The Isoperimetric Inequality
May
18
awarded  Yearling
May
7
awarded  Caucus
Apr
28
awarded  Enlightened