53,407 reputation
4110198
bio website
location
age
visits member for 4 years, 1 month
seen Sep 16 at 1:50

Don't have much time these days...


Jul
10
awarded  Nice Answer
Jul
9
revised filling an occluded plane with the smallest number of rectangles
edited tags
Jul
9
comment Integration using Lebesgue dominated convergence theorem
@ChristianRemling: Please see this: meta.math.stackexchange.com/questions/1559/…. There are advantages in having an "official" answer (rather than a comment).
Jul
8
revised Where can I find introductory video lectures about calculus and analysis?
edited tags
Jul
8
comment Fibonacci Numbers Proof
@robjohn: Yeah it is interesting. In fact, this approach provides many other identities too.
Jul
8
answered Fibonacci Numbers Proof
Jul
8
revised Is the fact that there are more irrational numbers than rational numbers useful?
edited tags
Jul
6
comment Evaluating a sum involving binomial coefficient in denominator
@PranavArora: No problem :-)
Jul
4
comment Rewrite and approximate the sum as an Integral $\sum_{i=1}^{1000} \sqrt{i}$
@Steven: Already appeared before: math.stackexchange.com/questions/5676/…. There is also an elementary proof which does not use Euler-Maclaurin.
Jul
4
revised Initial value of Newton Raphson Method
edited tags
Jul
4
comment Is my theorem correct? $f(x) \leq g(x)$ for $x\geq a$ iff $f'(x) \leq g'(x)$ for $x\geq a$ and $f(a)=g(a)$.
@MPW: The "theorem statement" is not well written. For instance, $f(a) = g(a)$ apparently is a consequence of $f \le g$, which I am pretty sure isn't what OP intends.
Jul
4
comment Is my theorem correct? $f(x) \leq g(x)$ for $x\geq a$ iff $f'(x) \leq g'(x)$ for $x\geq a$ and $f(a)=g(a)$.
The theorem is the Mean-Value-Theorem. See this: dpmms.cam.ac.uk/~wtg10/meanvalue.html. The corollary is probably too trivial a consequence to merit a name. (I haven't heard of one). Of course, trying to prove it independent of the MVT might be interesting (the page I link has some discussion in that direction).
Jul
4
comment Is my theorem correct? $f(x) \leq g(x)$ for $x\geq a$ iff $f'(x) \leq g'(x)$ for $x\geq a$ and $f(a)=g(a)$.
@FifaEarthCup2014: What do you mean by that? One way is true (inequality between derivatives implying the inequality between the functions), but it is an easy to show corollary of a well known theorem and almost anyone who has some calculus experience knows it like the back of their hand.
Jul
4
answered Solve $\lim_{x\to 0} \frac{\sin x-x}{x^3}$
Jul
4
answered Is my theorem correct? $f(x) \leq g(x)$ for $x\geq a$ iff $f'(x) \leq g'(x)$ for $x\geq a$ and $f(a)=g(a)$.
Jul
3
answered $\cos x -1+\frac{x^2}{2!} \geq 0$ for every $x\in \mathbb{R} $
Jul
3
revised When does $(a,b) \to (2a, b-a)$ terminate? ($a \leq b$)
deleted 55 characters in body
Jul
3
revised How many decimal representations are possible for the number 1
edited tags
Jul
3
comment Zombie outbreak on a $k$-regular graph
@AlexanderGruber: :-). Yeah, I had actually guessed that you were the author (hence the exclamation at the end of my previous comment).
Jul
3
revised When does $(a,b) \to (2a, b-a)$ terminate? ($a \leq b$)
deleted 19 characters in body