Aryabhata
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397/400 score
 Feb10 comment Comparing $\pi^{e}$ and $e^{\pi}$ @NikolajK: Thank you for the suggestion! Done. Feb10 revised Comparing $\pi^{e}$ and $e^{\pi}$ added 48 characters in body Feb9 awarded Enlightened Feb9 awarded Nice Answer Feb8 awarded Nice Answer Feb1 comment Irrational numbers in reality @AsafKaragila: Thanks! Did not know the 60 day thing. The flag was declined with a comment that this is not about physics (which I disagree with) and it is too late to migrate (they didn't mention the 60 day thing). Jan30 revised Convergent or Divergent? $\sum_{n=1}^\infty\bigl(2^{\frac1{n}}-1\bigr)$ added 64 characters in body Jan30 comment Convergent or Divergent? $\sum_{n=1}^\infty\bigl(2^{\frac1{n}}-1\bigr)$ @DepeHb: Uh. You are right! Thanks for pointing that out. That is easily fixed, fortunately (take $\frac{1}{\sqrt{2}}$ instead)... Jan29 comment Help with $\lim_{x\rightarrow +\infty} (x^2 - \sqrt{x^4 - x^2 + 1})$ You are welcome. Jan29 revised Proving that $\sin1$(radian) is irrational without using Taylor Series Expansion. edited tags Jan29 comment Proving that $\sin1$(radian) is irrational without using Taylor Series Expansion. btw, if it was $\sin 1^{\circ}$, the proof would be easy: $\sin 45^{\circ}$ is a polynomial in $\sin 1^{\circ}$ with rational (in fact, integer) coefficients! Since $\sin 45^{\circ}$ is irrational... Jan29 answered Proving that $\sin1$(radian) is irrational without using Taylor Series Expansion. Jan29 revised Proving that $\sin1$(radian) is irrational without using Taylor Series Expansion. edited tags Jan29 comment Irrational numbers in reality This is not a mathematical question. Seems like you found a bug around getting close votes by offering a bounty :-) I have flagged for migration to physics.se, so let's see. Jan27 comment Can't figure out $O(n \log n)$ divide-and-conquer algorithm You could implement so it is $\Omega(n \log n)$ instead of $O(n)$ though... Jan27 revised Can't figure out $O(n \log n)$ divide-and-conquer algorithm edited tags Jan27 comment Can't figure out $O(n \log n)$ divide-and-conquer algorithm This is the famous maximum sum subarray problem... Jan27 answered Can't figure out $O(n \log n)$ divide-and-conquer algorithm Jan27 comment Why $\sum_{j=1}^mj^p \sim m^{p+1}$ as $n\to\infty$? @Lionville: Ok, good to know you haven't ignored it completely :-) Jan27 comment How to proceed with the following integration? Manish, this site has latex support using MathJax, please use it instead of posting image links. Here is a reference: meta.math.stackexchange.com/questions/5020/…