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Nov
15
comment Polynomials, derivatives and repeated roots
@Arturo: Given the way the question was phrased, I am confident this is $\mathbb{R}[x]$ or $\mathbb{C}[x]$. (Looks more like a high-school/beginning college level question to me).
Nov
15
comment Polynomials, derivatives and repeated roots
@Qia: Why can't we assume that in $\mathbb{R}[x]$?
Nov
15
answered Polynomials, derivatives and repeated roots
Nov
15
comment Recurrence trouble: $T(n)=2T(n/2)+T(n/3)+\theta(n^2)$
@ECE: What do you mean by better result? Akra-Bazzi immediately shows that T(n) = theta(n^2). What more are you expecting?
Nov
15
comment Recurrence trouble: $T(n)=2T(n/2)+T(n/3)+\theta(n^2)$
@ECE: A better way is Akra-Bazzi as I just described! If this is homework and you are expecting a simpler answer, please say so.
Nov
15
comment Recurrence trouble: $T(n)=2T(n/2)+T(n/3)+\theta(n^2)$
@ECE: I still have no clue what you are trying to say. I have edited the answer to add more information.
Nov
15
revised Recurrence trouble: $T(n)=2T(n/2)+T(n/3)+\theta(n^2)$
added 216 characters in body; added 56 characters in body
Nov
15
comment Recurrence trouble: $T(n)=2T(n/2)+T(n/3)+\theta(n^2)$
@ECE: What? I don't understand.
Nov
15
revised Recurrence trouble: $T(n)=2T(n/2)+T(n/3)+\theta(n^2)$
added 57 characters in body; edited title; deleted 15 characters in body; edited title; added 1 characters in body
Nov
15
answered Recurrence trouble: $T(n)=2T(n/2)+T(n/3)+\theta(n^2)$
Nov
15
answered How to find the logical formula for a given truth table?
Nov
14
revised Calculate point on hypotenuse of right-angled triangle
deleted 62 characters in body
Nov
14
revised Does the series $\sum\limits_{n=1}^{\infty}\frac{\sin(n-\sqrt{n^2+n})}{n}$ converge?
added 18 characters in body; edited title
Nov
14
comment Does the series $\sum\limits_{n=1}^{\infty}\frac{\sin(n-\sqrt{n^2+n})}{n}$ converge?
+1 for showing the effort.
Nov
14
comment How to calculate the expected number of distinct items when drawing pairs?
+1: For the effort!
Nov
14
comment Given $a_{1}=1, \ a_{n+1}=a_{n}+\frac{1}{a_{n}}$, find $\lim \limits_{n\to\infty}\frac{a_{n}}{n}$
@daniel: No need to forget, it actually can be made to work!
Nov
14
comment Given $a_{1}=1, \ a_{n+1}=a_{n}+\frac{1}{a_{n}}$, find $\lim \limits_{n\to\infty}\frac{a_{n}}{n}$
you need a little more steps to get rid of Sum (1/a_k_^2)
Nov
14
comment Given $a_{1}=1, \ a_{n+1}=a_{n}+\frac{1}{a_{n}}$, find $\lim \limits_{n\to\infty}\frac{a_{n}}{n}$
@daniel: How did you get rid if Sum (1/a_k_^2) ? btw 2 is correct :-)
Nov
14
comment Given $a_{1}=1, \ a_{n+1}=a_{n}+\frac{1}{a_{n}}$, find $\lim \limits_{n\to\infty}\frac{a_{n}}{n}$
Very interesting. Well done :-)
Nov
14
awarded  calculus