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Don't have much time these days...


Nov
3
comment Why does the polynomial equation $1 + x + x^2 + \cdots + x^n = S$ have at most two solutions in $x$?
@Willie: The derivative is particularly nice and trying to visualize the graph is always intuitive :-)
Nov
3
comment Why does the polynomial equation $1 + x + x^2 + \cdots + x^n = S$ have at most two solutions in $x$?
@Rahul: You are right. I have edited it.
Nov
3
revised Why does the polynomial equation $1 + x + x^2 + \cdots + x^n = S$ have at most two solutions in $x$?
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Nov
3
revised Why does the polynomial equation $1 + x + x^2 + \cdots + x^n = S$ have at most two solutions in $x$?
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Nov
3
comment Summing a given series
Even thought the indefinite integral is hard, there might be ways to find the definite integral...
Nov
3
comment Why does the polynomial equation $1 + x + x^2 + \cdots + x^n = S$ have at most two solutions in $x$?
@Rahul: I suppose this is similar as what you have. I think this is quite simple and intuitive, though.
Nov
3
revised Why does the polynomial equation $1 + x + x^2 + \cdots + x^n = S$ have at most two solutions in $x$?
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Nov
3
revised Why does the polynomial equation $1 + x + x^2 + \cdots + x^n = S$ have at most two solutions in $x$?
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Nov
3
answered Why does the polynomial equation $1 + x + x^2 + \cdots + x^n = S$ have at most two solutions in $x$?
Nov
3
revised Find an infinite set of positive integers such that the sum of any two distinct elements has an even number of distinct prime factors
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Nov
3
revised Continued Fraction expansion of tan(1)
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Nov
3
answered Continued Fraction expansion of tan(1)
Nov
1
comment Convergence of a series and respective sum
If this is homework, please consider tagging it as such.
Nov
1
revised Find an infinite set of positive integers such that the sum of any two distinct elements has an even number of distinct prime factors
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Oct
30
comment Adding integers to an infinite continued fraction expansion doesn't change the value?
+1: Now I agree with this :-)
Oct
30
revised Adding integers to an infinite continued fraction expansion doesn't change the value?
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Oct
30
answered proving $\sum\limits_{k=1}^{n} \Bigl\lfloor{\frac{k}{a}\Bigr\rfloor} =\Bigl\lfloor{\frac{(2n+b)^{2}}{8a}\Bigr\rfloor} $
Oct
30
comment Adding integers to an infinite continued fraction expansion doesn't change the value?
@CRom: Yes, you also need to mention that $\beta_n = \langle a_0, a_1, \dots, a_n, b_1, b_2, \dots \rangle $. Other that, it looks fine to me. btw, nicely done!
Oct
29
revised Adding integers to an infinite continued fraction expansion doesn't change the value?
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Oct
29
revised Adding integers to an infinite continued fraction expansion doesn't change the value?
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