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Nov
16
answered Existence of circuit passing through each vertex in a directed graph
Nov
16
comment Probability in a game of Contract Bridge
@Ross: Yes, that is correct. By "3-2" I meant 3-2 and 2-3 etc. It is common among bridge players :-)
Nov
16
revised Probability in a game of Contract Bridge
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Nov
16
answered Probability in a game of Contract Bridge
Nov
15
comment Newbie question about the re-application of a function on its result
@Sklivv: Yes, It didn't seem an exact dupe and that is why I didn't cast my close vote :-)
Nov
15
comment Newbie question about the re-application of a function on its result
@Hans: Yes that is it.
Nov
15
comment Newbie question about the re-application of a function on its result
I believe this is a dupe. Unfortunately I am not able to find the previous one.
Nov
15
comment Proving an identity involving terms in arithmetic progression.
@Deb: I was talking about "Prove an Identity" or whatever you had before.
Nov
15
comment Proving an identity involving terms in arithmetic progression.
@Debanjan: If you don't want to mug it, I suggest you try it first. At least edit the question with the ideas you had.
Nov
15
comment Proving an identity involving terms in arithmetic progression.
@Debanjan: What have you tried so far?
Nov
15
comment Proving an identity involving terms in arithmetic progression.
@Chandru: Yes. a_i are in arithmetic progression, I believe.
Nov
15
answered What is the length of a continued fraction expansion of a rational number?
Nov
15
comment Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$
Not sure what you mean. All I am saying is that it can be written in terms of well known constants. I guess we are just agreeing :-)
Nov
15
revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$
added 117 characters in body; added 12 characters in body
Nov
15
comment Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$
If you assume the Dottie number to be part of the "closed form" constants, then there is a closed form solution. See my answer.
Nov
15
revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$
added 25 characters in body; added 8 characters in body; added 41 characters in body
Nov
15
revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$
added 193 characters in body; deleted 104 characters in body; deleted 7 characters in body; added 290 characters in body
Nov
15
revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$
added 17 characters in body; added 62 characters in body
Nov
15
revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$
added 7 characters in body; edited title; added 1 characters in body
Nov
15
revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$
added 178 characters in body; added 3 characters in body; added 60 characters in body; added 14 characters in body