Aryabhata
Reputation
60,464
416/400 score
 Nov 16 answered Existence of circuit passing through each vertex in a directed graph Nov 16 comment Probability in a game of Contract Bridge @Ross: Yes, that is correct. By "3-2" I meant 3-2 and 2-3 etc. It is common among bridge players :-) Nov 16 revised Probability in a game of Contract Bridge deleted 2 characters in body Nov 16 answered Probability in a game of Contract Bridge Nov 15 comment Newbie question about the re-application of a function on its result @Sklivv: Yes, It didn't seem an exact dupe and that is why I didn't cast my close vote :-) Nov 15 comment Newbie question about the re-application of a function on its result @Hans: Yes that is it. Nov 15 comment Newbie question about the re-application of a function on its result I believe this is a dupe. Unfortunately I am not able to find the previous one. Nov 15 comment Proving an identity involving terms in arithmetic progression. @Deb: I was talking about "Prove an Identity" or whatever you had before. Nov 15 comment Proving an identity involving terms in arithmetic progression. @Debanjan: If you don't want to mug it, I suggest you try it first. At least edit the question with the ideas you had. Nov 15 comment Proving an identity involving terms in arithmetic progression. @Debanjan: What have you tried so far? Nov 15 comment Proving an identity involving terms in arithmetic progression. @Chandru: Yes. a_i are in arithmetic progression, I believe. Nov 15 answered What is the length of a continued fraction expansion of a rational number? Nov 15 comment Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$ Not sure what you mean. All I am saying is that it can be written in terms of well known constants. I guess we are just agreeing :-) Nov 15 revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$ added 117 characters in body; added 12 characters in body Nov 15 comment Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$ If you assume the Dottie number to be part of the "closed form" constants, then there is a closed form solution. See my answer. Nov 15 revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$ added 25 characters in body; added 8 characters in body; added 41 characters in body Nov 15 revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$ added 193 characters in body; deleted 104 characters in body; deleted 7 characters in body; added 290 characters in body Nov 15 revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$ added 17 characters in body; added 62 characters in body Nov 15 revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$ added 7 characters in body; edited title; added 1 characters in body Nov 15 revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$ added 178 characters in body; added 3 characters in body; added 60 characters in body; added 14 characters in body