Aryabhata
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 Nov15 comment Newbie question about the re-application of a function on its result @Hans: Yes that is it. Nov15 comment Newbie question about the re-application of a function on its result I believe this is a dupe. Unfortunately I am not able to find the previous one. Nov15 comment Proving an identity involving terms in arithmetic progression. @Deb: I was talking about "Prove an Identity" or whatever you had before. Nov15 comment Proving an identity involving terms in arithmetic progression. @Debanjan: If you don't want to mug it, I suggest you try it first. At least edit the question with the ideas you had. Nov15 comment Proving an identity involving terms in arithmetic progression. @Debanjan: What have you tried so far? Nov15 comment Proving an identity involving terms in arithmetic progression. @Chandru: Yes. a_i are in arithmetic progression, I believe. Nov15 answered What is the length of a continued fraction expansion of a rational number? Nov15 comment Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$ Not sure what you mean. All I am saying is that it can be written in terms of well known constants. I guess we are just agreeing :-) Nov15 revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$ added 117 characters in body; added 12 characters in body Nov15 comment Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$ If you assume the Dottie number to be part of the "closed form" constants, then there is a closed form solution. See my answer. Nov15 revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$ added 25 characters in body; added 8 characters in body; added 41 characters in body Nov15 revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$ added 193 characters in body; deleted 104 characters in body; deleted 7 characters in body; added 290 characters in body Nov15 revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$ added 17 characters in body; added 62 characters in body Nov15 revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$ added 7 characters in body; edited title; added 1 characters in body Nov15 revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$ added 178 characters in body; added 3 characters in body; added 60 characters in body; added 14 characters in body Nov15 answered Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$ Nov15 revised Given $a_{1}=1, \ a_{n+1}=a_{n}+\frac{1}{a_{n}}$, find $\lim \limits_{n\to\infty}\frac{a_{n}}{n}$ added 134 characters in body Nov15 revised Given $a_{1}=1, \ a_{n+1}=a_{n}+\frac{1}{a_{n}}$, find $\lim \limits_{n\to\infty}\frac{a_{n}}{n}$ added 1876 characters in body; added 152 characters in body; added 2 characters in body; added 30 characters in body; added 85 characters in body Nov15 comment How can one efficiently generate n small relatively prime integers? @Charles: The whole point of the question is to generate small numbers which are relative prime and if possible in linear time. This answer does not help in that regard (the reason for my -1). The mistakes are irrelevant. Nov15 comment $G$ finite abelian. $G/H$, $G/K$ primary cyclic. $H\cap K=1$. $H\neq 1\neq K$. Is $HK=G$? +1 for showing the attempt.