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Nov
15
comment Newbie question about the re-application of a function on its result
@Hans: Yes that is it.
Nov
15
comment Newbie question about the re-application of a function on its result
I believe this is a dupe. Unfortunately I am not able to find the previous one.
Nov
15
comment Proving an identity involving terms in arithmetic progression.
@Deb: I was talking about "Prove an Identity" or whatever you had before.
Nov
15
comment Proving an identity involving terms in arithmetic progression.
@Debanjan: If you don't want to mug it, I suggest you try it first. At least edit the question with the ideas you had.
Nov
15
comment Proving an identity involving terms in arithmetic progression.
@Debanjan: What have you tried so far?
Nov
15
comment Proving an identity involving terms in arithmetic progression.
@Chandru: Yes. a_i are in arithmetic progression, I believe.
Nov
15
answered What is the length of a continued fraction expansion of a rational number?
Nov
15
comment Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$
Not sure what you mean. All I am saying is that it can be written in terms of well known constants. I guess we are just agreeing :-)
Nov
15
revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$
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Nov
15
comment Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$
If you assume the Dottie number to be part of the "closed form" constants, then there is a closed form solution. See my answer.
Nov
15
revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$
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Nov
15
revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$
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Nov
15
revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$
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Nov
15
revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$
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Nov
15
revised Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$
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Nov
15
answered Solving $2x - \sin 2x = \pi/2$ for $0 < x < \pi/2$
Nov
15
revised Given $a_{1}=1, \ a_{n+1}=a_{n}+\frac{1}{a_{n}}$, find $\lim \limits_{n\to\infty}\frac{a_{n}}{n}$
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Nov
15
revised Given $a_{1}=1, \ a_{n+1}=a_{n}+\frac{1}{a_{n}}$, find $\lim \limits_{n\to\infty}\frac{a_{n}}{n}$
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Nov
15
comment How can one efficiently generate n small relatively prime integers?
@Charles: The whole point of the question is to generate small numbers which are relative prime and if possible in linear time. This answer does not help in that regard (the reason for my -1). The mistakes are irrelevant.
Nov
15
comment $G$ finite abelian. $G/H$, $G/K$ primary cyclic. $H\cap K=1$. $H\neq 1\neq K$. Is $HK=G$?
+1 for showing the attempt.