Reputation
57,033
Next tag badge:
397/400 score
77/80 answers
Badges
4 120 211
Impact
~1.0m people reached

Mar
28
comment Counting the number of integers $i$ such that $\sigma(i)$ is even.
Is this an algorithm problem? Assuming it is, retagging as elementary-number-theory.
Mar
26
comment Calculation of limit without stirling approximation
A previous answer of mine proves this in a completely elementary fashion: math.stackexchange.com/a/131084/1102. Falls right out of Proposition E.
Mar
26
comment Can the sum of reciprocals of a set without density converge?
Convergence implies density is zero. See: math.stackexchange.com/questions/5932/…
Mar
26
revised Proof : Limit of a sequence
edited tags
Mar
19
comment Aproximation of $a_n$ where $a_{n+1}=a_n+\sqrt {a_n}$
+1: Nice.......
Mar
19
revised Aproximation of $a_n$ where $a_{n+1}=a_n+\sqrt {a_n}$
more informative title.
Mar
19
comment Aproximation of $a_n$ where $a_{n+1}=a_n+\sqrt {a_n}$
This is not pedantry. I don't think this is as trivial as you seem to be implying. Unless you have a proof, you are just handwaving. Anyway, you are free not to elaborate, and I am free to leave the downvote intact.
Mar
19
revised Aproximation of $a_n$ where $a_{n+1}=a_n+\sqrt {a_n}$
edited tags
Mar
19
comment Aproximation of $a_n$ where $a_{n+1}=a_n+\sqrt {a_n}$
Please take at least a day or two before accepting an answer. In this case, the accepted answer is incomplete.
Mar
19
comment Aproximation of $a_n$ where $a_{n+1}=a_n+\sqrt {a_n}$
The heuristic is only a first step. Making it rigorous is the hard part. -1 till there is a proof. Sorry.
Mar
18
comment Quotient of a regular language
@AstroNauft: You don't need to determine anything. It is a non-constructive proof. $L$ could be any language.
Mar
18
comment The limit : $ \lim _{x \to \infty } \sqrt{x^2 +x} - \sqrt{x^2 +1} $
Related: math.stackexchange.com/questions/30040/…
Mar
17
comment How to show that $\lim_{n \to +\infty} n^{\frac{1}{n}} = 1$?
@ADG: It is my name, I will spell it as I want! :-). Just kidding :-). Apparently, it is actually Aryabhata and not Aryabhatta. In fact I had it as Aryabhatta till ShreevatsaR corrected me.
Mar
15
awarded  Nice Answer
Mar
13
revised Big O notation and limits
edited tags
Mar
11
revised Inequality between real numbers $a^ab^bc^c<(abc)^{\frac{a+b+c}{3}}$
added 199 characters in body
Mar
8
comment Inequality between real numbers $a^ab^bc^c<(abc)^{\frac{a+b+c}{3}}$
If I haven't made any mistake that is... This looks too simple!
Mar
8
answered Inequality between real numbers $a^ab^bc^c<(abc)^{\frac{a+b+c}{3}}$
Feb
22
awarded  Nice Question
Feb
17
awarded  Good Answer