| bio | website | |
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| location | ||
| age | ||
| visits | member for | 2 years, 9 months |
| seen | 9 hours ago | |
| stats | profile views | 8,073 |
Don't have much time these days...
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3h |
awarded | Enlightened |
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3h |
awarded | Nice Answer |
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18h |
revised |
Reduction from Hamiltonian cycle to Hamiltonian path deleted 104 characters in body |
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1d |
awarded | Enlightened |
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2d |
revised |
Simple Number Theory Question edited tags |
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May 19 |
answered | Prove that $(1+1/x)^x$ is concave for $x>0$ |
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May 19 |
comment |
How to find area of triangle from its medians Thanks! I see it now :-) +1. |
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May 19 |
comment |
How to find area of triangle from its medians What right triangle? Can you please elaborate? |
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May 19 |
revised |
Generalizing $\sum \limits_{n=1}^{\infty }n^{2}/x^{n}$ to $\sum \limits_{n=1}^{\infty }n^{p}/x^{n}$ added 6 characters in body |
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May 19 |
comment |
Closed form for n-th anti-derivative of $\log x$ You can add an arbitrary $(n-1)^{\text{th}}$ degree polynomial... |
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May 19 |
comment |
Closed form for n-th anti-derivative of $\log x$ @Argon: Even though I cast a close vote, I now believe it is slightly different, as the $H_n$ term becomes important for $\log x$, but not for $\frac{1}{x}$. |
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May 19 |
comment |
How to find area of triangle from its medians You can also use Appolonius theorem. |
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May 18 |
comment |
Using the hypothesis $\frac{1}{a}+\frac{1}{b}+\frac{1}{c}=\frac{1}{a+b+c}$ to prove something else @cruise: I say it is pointless because there is essentially no non-trivial mathematical content there. Anyway, you are entitled to your opinion, as I am mine (and so do the other downvoters/upvoters). I only commented because you seemed interested to know why you got downvotes. I tried to give you the reason why I gave a downvote. Let's leave it at that. It is clear that there won't be an agreement. (btw, you seem to conveniently choose to ignore the 5 downvotes and talk about the solitary upvote you got :-)). |
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May 18 |
revised |
Find the minimum of $q$. edited tags |
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May 18 |
comment |
Using the hypothesis $\frac{1}{a}+\frac{1}{b}+\frac{1}{c}=\frac{1}{a+b+c}$ to prove something else @cruise: I gathered that for the previous comments. But really, the interpretation you chose is quite pointless. |
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May 17 |
revised |
why is $\sum\limits_{k=1}^{n} k^m$ a polynomial with degree $m+1$ in $n$ added 12 characters in body |
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May 17 |
answered | Identity with Bernoulli numbers: $\sum\limits_{k=1}^{n}k^p=\frac{1}{p+1}\sum\limits_{j=0}^{p}\binom{p+1}{j}B_j n^{p+1-j}$ |
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May 17 |
revised |
Integrate: $\int_0^{\infty} \frac{\sin (ax)}{e^{\pi x} \sinh(\pi x)}dx$ edited tags |
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May 17 |
answered | Using the hypothesis $\frac{1}{a}+\frac{1}{b}+\frac{1}{c}=\frac{1}{a+b+c}$ to prove something else |
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May 17 |
comment |
Using the hypothesis $\frac{1}{a}+\frac{1}{b}+\frac{1}{c}=\frac{1}{a+b+c}$ to prove something else -1: The interpretation in this answer is nonsensical. Sorry. |