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comment How to show that $\lim_{n \to +\infty} n^{\frac{1}{n}} = 1$?
@Quintic: $x_1 = x_2 = \dots = x_{n-2} = 1, x_{n-1} = x_n = \sqrt{n}$.
Apr
13
revised $1989 \mid n^{n^{n^{n}}} - n^{n^{n}}$ for integer $n \ge 3$
edited tags
Apr
11
comment How to show that $\lim_{n \to +\infty} n^{\frac{1}{n}} = 1$?
@Subhadeep: Wow! Thanks!...
Mar
11
awarded  Nice Answer
Mar
9
awarded  Enlightened
Mar
9
awarded  Nice Answer
Feb
17
revised Prove that angle ACB > angle ABD.
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Feb
2
awarded  Good Answer
Jan
30
awarded  Great Answer
Jan
28
awarded  Guru
Jan
22
comment Proving that a sequence is bounded without knowing the sequence explicitly
What is the starting value?
Jan
21
revised Diophantine equation with $gcd = 1$
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Jan
18
awarded  Notable Question
Jan
7
awarded  Enlightened
Jan
7
awarded  Nice Answer
Jan
6
comment Computing limits which involve square roots, such as $\sqrt{n^2+n}-n$
@Normal: I suggest you read this: meta.math.stackexchange.com/questions/1868/… and the linked question by Bill D. Special case vs general case is a common objection to such closings, but such closings [i.e. closed as minor variations] are fine IMO. It does not have to be an exact dupe.
Jan
4
comment Computing limits which involve square roots, such as $\sqrt{n^2+n}-n$
Please consider browsing the faq tag before posting a question. [To anyone who comes across this comment, I know this question is old]
Jan
4
comment Computing limits which involve square roots, such as $\sqrt{n^2+n}-n$
Possible duplicate of Limits: How to evaluate $\lim\limits_{x\rightarrow \infty}\sqrt[n]{x^{n}+a_{n-1}x^{n-1}+\cdots+a_{0}}-x$
Dec
31
awarded  Good Answer
Dec
26
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