| bio | website | |
|---|---|---|
| location | Colorado and Lincoln, NE | |
| age | 20 | |
| visits | member for | 2 years |
| seen | Apr 20 at 2:21 | |
| stats | profile views | 67 |
Computer Science Undergraduate at UNL. C#, .NET 4.5, Windows 8 lover.
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Sep 12 |
asked | Truth Value of Theorems in Axiomatic Set Theory |
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May 29 |
answered | Mathematical Career Advice to a young 16 year wannabe mathematician |
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May 16 |
awarded | Supporter |
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May 16 |
awarded | Commentator |
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May 16 |
accepted | Finding the limit when denominator = 0 |
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May 16 |
comment |
Finding the limit when denominator = 0 This makes perfect sense! Thank you! |
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May 16 |
awarded | Editor |
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May 16 |
revised |
Finding the limit when denominator = 0 added 349 characters in body |
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May 16 |
comment |
Finding the limit when denominator = 0 Thank you, that does make sense (of course DNE being the same thing as + or - infinity - + in this case). When I asked this question, I didn't know that it was positive both ways. Can you explain how to get + or - infinity from the following problem? $$\lim_{x \to 3^+} \frac{x - 4}{x - 3}$$ |
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May 16 |
comment |
Finding the limit when denominator = 0 Yes, but what if the problem is $$\lim_{x \to 3^+} \frac{x - 4}{x - 3}$$. Approached from the right, it is $-\infty$ and from the left, it is $+\infty$. How do I tell if it is positive or negative infinity without graphing it or plugging in numbers? |
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May 16 |
comment |
Finding the limit when denominator = 0 Thanks for the answer, but I'm having trouble understanding this (I'm reviewing for a Calc 1 final). I'm not sure what $\forall$ and $\in$ are. Also, I'm not sure what M stands for. |
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May 16 |
comment |
Finding the limit when denominator = 0 I know that I could do it like that, but that's still plugging in values (albeit inside your head). I'm interested to find a way to solve it without plugging in numbers (even if it's in your head) or graphing it. It makes more sense to me if I can understand how the math works in an absolute sense. |
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May 16 |
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Finding the limit when denominator = 0 I did not know you could change limits like that. If I change $$\lim_{x \to -2^-}$$ to $$\lim_{x \to 0^-}$$ what must happen to the rest of the function? Is there a rule for this? |
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May 16 |
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Finding the limit when denominator = 0 yes, but the question is how do I solve it without plotting? how do I know that it goes to infinity and if it is positive or negative? |
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May 16 |
asked | Finding the limit when denominator = 0 |
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May 16 |
awarded | Scholar |
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May 16 |
accepted | Finding a one sided limit algebraically (not plugging in numbers) |
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May 16 |
comment |
Finding a one sided limit algebraically (not plugging in numbers) @Tyler - Can you give an example of working that out? |
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May 16 |
awarded | Student |
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May 16 |
comment |
Finding a one sided limit algebraically (not plugging in numbers) and what about equations such as lim(x->-2 from the left) of 1/(x+2)^2 |