Caleb Jares
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 Feb28 comment In a group $G$ with operation $\star$, can I apply $\star$ to both sides of an equation? @GerryMyerson Isn't going from $a^2=b^2$ to $a=b$ the same as $a^2=b^2\implies a=b^2/a$, and because $a=b$, $\implies a=b^2/b=b$. Feb27 accepted In a group $G$ with operation $\star$, can I apply $\star$ to both sides of an equation? Feb27 asked In a group $G$ with operation $\star$, can I apply $\star$ to both sides of an equation? Feb25 awarded Excavator Feb25 revised what is difference between a ring and a field Added abelian group, formatted into a list. Feb25 suggested approved edit on what is difference between a ring and a field Feb15 revised Proving $4^{47}\equiv 4\pmod{12}$ edited tags Feb14 revised Proving $4^{47}\equiv 4\pmod{12}$ added additional info on 2nd line. Feb14 comment Proving $4^{47}\equiv 4\pmod{12}$ Thanks, this is a great way to prove it without induction! Feb14 suggested approved edit on Proving $4^{47}\equiv 4\pmod{12}$ Feb14 accepted Proving $4^{47}\equiv 4\pmod{12}$ Feb14 revised Proving $4^{47}\equiv 4\pmod{12}$ edited body Feb14 asked Proving $4^{47}\equiv 4\pmod{12}$ Jan21 awarded Notable Question Oct22 accepted Evaluating $\sum\limits_{n=0}^{20} \frac{(-1)^{n}2^{n+1}}{3^{n}},$ Sep19 awarded Popular Question Jun22 comment When representing a base-n number in decimal ($\frac{x}{n^l}$), will there be a different set of terminating representable numbers than base-10? Both mean the same thing. If there's a different set of terminating numbers there will also be a set of non-terminating numbers. Correct? Jun22 comment When representing a base-n number in decimal ($\frac{x}{n^l}$), will there be a different set of terminating representable numbers than base-10? You confirm my revised suspicion: the set of representable non-terminating numbers does depend on the base. Thanks! Jun22 revised When representing a base-n number in decimal ($\frac{x}{n^l}$), will there be a different set of terminating representable numbers than base-10? Misused rationality :) Jun22 comment When representing a base-n number in decimal ($\frac{x}{n^l}$), will there be a different set of terminating representable numbers than base-10? Yes, this is what I mean.