Reputation
4,332
Next privilege 5,000 Rep.
Approve tag wiki edits
Badges
13 27
Newest
 Yearling
Impact
~49k people reached

1d
reviewed Reject Time complexity for the multiplication of three rectangular matrix
1d
reviewed Approve Find the correct betting combination
May
6
awarded  Yearling
Apr
28
awarded  Custodian
Apr
28
reviewed Edit Can the given transformation possible for given determinant?
Apr
28
revised Can the given transformation possible for given determinant?
added 6 characters in body
Apr
28
reviewed Leave Open Show that $\sin\left(\frac\pi3(x-2)\right)$ is equal to $\cos\left(\frac\pi3(x-7/2)\right)$
Apr
28
awarded  Custodian
Apr
16
answered Evaluating norm of the operator
Apr
13
reviewed Approve Lagrange multipliers in Calculus of Variations
Apr
13
reviewed Approve How to prove this inequality? $(a+b+c=1)$
Apr
13
comment Degree of an extension of $ \mathbb{Q} $
A basis of $\mathbb{Q}(\alpha)$ is given by the powers of $\alpha$ (up to the degree of the extension minus one).
Apr
13
reviewed Reject Showing $\sum\frac{\sin(nx)}{n}$ converges pointwise
Apr
13
reviewed Approve Eigenvectors belonging to different eigenvalues are linearly indepenent. Problem with proof.
Apr
12
comment A problem from Artin
To give you an intuition, the generator of $\ker \varphi$ will be the "simplest" polynomial equation satisfied by $x$ and $y$ if you set $x = t^2 - t$ and $y = t^3 - t^2$ (it amounts to the "simplest" Cartesian equation for the parametric curve $(x,y) = (t^2-t, t^3-t^2)$). Here we have $y = tx$, so $x = \left(\frac{y}{x}\right)^2 + \frac{y}{x}$. We multiply by $x^2$ to get a polynomial equation $x^3 - y^2 - xy = 0$. So $f = x^3 - y^2 - xy$ should be the generator of $\ker \varphi$.
Dec
14
comment Number of ways to choose 6 books out of 20 books such that no 2 are adjacent books
As I understand the solution, $1$ always denotes a pair (book, no book), except if for the last $1$ in the sequence (for example $101$ means (book, no book, no book, book) and $110$ means (book, no book, book, no book)). With this convention there is no ambiguity and no need for the $2$.
Oct
22
awarded  Nice Answer
Oct
13
reviewed Approve Understanding Borel sets
Sep
30
reviewed Approve Weird limit problem
Jun
13
reviewed Approve Intro to Real Analysis