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Jun
30
comment Integral involving a trig. term
Doesn't the fact that you've written the $dx$ to the left of the function you are trying to integrate matter? (I understand what you're saying, and my comment is entirely tangential: I just feel that what you've written doesn't actually makes sense, but would be interested if my intuition was wrong...)
Jun
30
revised how can we make 20 using onlynand only two 3s and we can use any mathematical function as and when required
deleted 137 characters in body
Jun
25
comment How to integrate $\int^{\infty}_{-\infty} e^{-2\pi^2/x^2} dx$?
You need brackets. Do you mean $\displaystyle\frac{e^{-2\pi}}{x^2}$? Or $\displaystyle\frac{e^{-2}\pi}{x^2}$ Or $\displaystyle\left(\frac{e^{-2\pi}}{x}\right)^2$? Or something else?
Jun
25
asked $e^{i\theta}$ versus $\cos\theta+i\sin\theta$
Jun
15
revised Is every normal subgroup of a finitely generated free group a normal closure of a finite set?
added 156 characters in body
Jun
15
revised Is every normal subgroup of a finitely generated free group a normal closure of a finite set?
added 109 characters in body
Jun
15
answered Is every normal subgroup of a finitely generated free group a normal closure of a finite set?
Jun
15
comment How do I simplify the answer?
...assuming $x\neq-1$...
Jun
15
comment How do I simplify the answer?
@ClementC. I agree on all counts.
Jun
15
comment How do I simplify the answer?
I think downvoting this answer is not helpful, because the answer is itself helpful. Clearly the OP is having issues with the step given by the hint - the incorrect derivative is, in a certain sense, circumstantial.
Jun
15
revised How do I simplify the answer?
added 4 characters in body
Jun
1
comment Quotient of the Baumslag-Solitar group $BS(1,m)=\langle a,b| bab^{-1}=a^m\rangle$
@Derek Thanks. Again, I was too hasty!
Jun
1
comment Quotient of the Baumslag-Solitar group $BS(1,m)=\langle a,b| bab^{-1}=a^m\rangle$
@Derek Why is every element of $N$ conjugate to a power of $a$? For example, $b^{-1}aba^m\in N$, and by the conjugacy theorem for HNN-extensions we would need that $a^ib^{-1}aba^j=a^k$, which does not hold. No?
Jun
1
comment Quotient of the Baumslag-Solitar group $BS(1,m)=\langle a,b| bab^{-1}=a^m\rangle$
@Derek Thanks - I was too hasty. I've deleted both my comments.
May
29
revised Groups occuring as derived subgroups.
added 77 characters in body; edited title
May
19
revised Show that $\alpha: G \rightarrow G ,\alpha(g)=g^2$ isomorphism
added 2 characters in body
May
19
comment Show that $\alpha: G \rightarrow G ,\alpha(g)=g^2$ isomorphism
@ASKASK Yeah, probably. But still - at least write out the word fully!
May
19
comment Show that $\alpha: G \rightarrow G ,\alpha(g)=g^2$ isomorphism
I do not understand your attempt. What is "hom", and why is $G$ this?
May
19
revised Why Aren't “Similar” Matrices Actually the Same?
I used to be called Swlabr, a long time ago.
May
15
comment What does this vector notation really mean?
@vadim123 C'mon, this is a valid question. A similar one might be Is “a+0i” in every way equal to just “a”?.