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Jun
17
comment Constructing any function $\{1 \dots n\} \rightarrow \{1 \dots k\}$ using functions $\{1 \dots n \} \rightarrow \{1,2\}$
Oh, okay - thank you for it then:-)
Jun
17
comment Constructing any function $\{1 \dots n\} \rightarrow \{1 \dots k\}$ using functions $\{1 \dots n \} \rightarrow \{1,2\}$
It doesn't really have to be just $[N] \rightarrow [2]$ it can be any construction like: function of pair of functions, but with counterdomain $[2]$
Jun
17
asked Constructing any function $\{1 \dots n\} \rightarrow \{1 \dots k\}$ using functions $\{1 \dots n \} \rightarrow \{1,2\}$
Jun
15
awarded  Popular Question
Jun
1
awarded  Nice Question
May
3
awarded  Yearling
Apr
17
awarded  Notable Question
Apr
9
comment How to find function $f$ bounded from top by $x^\alpha$ and from bottom by $log^k(x)$
Thanks a lot Clement, this is very clever and nice solution, thanks a lot
Apr
9
accepted How to find function $f$ bounded from top by $x^\alpha$ and from bottom by $log^k(x)$
Apr
9
comment How to find function $f$ bounded from top by $x^\alpha$ and from bottom by $log^k(x)$
I edited question with little detail, sorry about it, i assumed it was obvious, cause simplest example $ln^2 x > x^2$ as x goes to 0 shows it couldn't be possible.
Apr
9
revised How to find function $f$ bounded from top by $x^\alpha$ and from bottom by $log^k(x)$
added 72 characters in body
Apr
9
comment How to find function $f$ bounded from top by $x^\alpha$ and from bottom by $log^k(x)$
Thanks peter for your comment, x should be greater than 0.
Apr
9
revised How to find function $f$ bounded from top by $x^\alpha$ and from bottom by $log^k(x)$
added 7 characters in body
Apr
9
comment How to find function $f$ bounded from top by $x^\alpha$ and from bottom by $log^k(x)$
@ClementC. it's looking very nice!
Apr
9
comment How to find function $f$ bounded from top by $x^\alpha$ and from bottom by $log^k(x)$
Hey @peter.petrov yes i'm sure
Apr
9
asked How to find function $f$ bounded from top by $x^\alpha$ and from bottom by $log^k(x)$
Apr
2
comment Is generating function having use in recurence relations containing division in subscripts?
You say $$\sum_{k=2}^r \lambda_k a_0 = a_0$$ That is not true when any $\lambda_k>1$. I understood $\lambda_k$ is constant standing next to $a_{\lfloor \frac{n}{k} \rfloor}$, right?
Apr
2
asked Is generating function having use in recurence relations containing division in subscripts?
Apr
1
accepted Generating function for sequence $a_n = \lceil \sqrt{n} \rceil $
Apr
1
comment Generating function for sequence $a_n = \lceil \sqrt{n} \rceil $
@MarcoCantarini thanks for this comment, but we don't need to care about convergence of this generating function as long as we don't substitute any value for x.