meta user
network profile
| bio | website | everybodyhatesluigi.com |
|---|---|---|
| location | Westminster, CO | |
| age | 93 | |
| visits | member for | 2 years, 1 month |
| seen | Jun 6 at 10:00 | |
| stats | profile views | 163 |
I like math.
|
Jun 7 |
awarded | Popular Question |
|
Jun 6 |
asked | Does mathematical induction assume that non-negative integers are infinite? |
|
Jun 1 |
awarded | Popular Question |
|
May 5 |
awarded | Informed |
|
May 1 |
awarded | Yearling |
|
Apr 16 |
awarded | Nice Question |
|
Nov 12 |
accepted | Space filling paths |
|
Nov 12 |
comment |
Space filling paths Yes that was my motivation: Cantor's diagonal argument and its implication that there are as many points in a line as in a plane or any other subset of $R^n$. I did not know that onto transformations from $R$ to $R^2$ where possible; I was under the impression that it was impossible, which is why I considered my transformation paradoxical, but if what you claim is true then there really is no paradox. I find it even more surprising that bijective mappings from $R$ to $R^2$ exist. |
|
Nov 12 |
asked | Space filling paths |
|
May 1 |
awarded | Yearling |
|
Apr 30 |
accepted | Squaring an arbitrary summation? |
|
Apr 30 |
comment |
Squaring an arbitrary summation? That makes perfect sense. You have earned a green check-mark. |
|
Apr 30 |
comment |
Squaring an arbitrary summation? @BrianM.Scott: Is the reasoning in my previous comment not a generalization of the product of two arbitrary polynomials? I thought we could just set $a_i=c_ix^i$ and derive the Cauchy product. |
|
Apr 30 |
comment |
Squaring an arbitrary summation? Say we have $\big(\sum_{i=0}^{n}a_i\big)\big(\sum_{j=0}^{n}b_j\big)$ $=a_0\big(\sum_{j=0}^{n}\big)+a_1\big(\sum_{j=0}^{n}\big)+...+a_n\big(\sum_{j=0}^{n}\big)$ which equals $\sum_{i=0}^{n}\sum_{j=0}^{n}a_ib_j$. Why do we shift the index of the second summation? |
|
Apr 30 |
asked | Squaring an arbitrary summation? |
|
Apr 18 |
comment |
Power series solution for a DE Well, I really do not understand what I am missing then. What am I supposed to do with that -1? I've been trying to get this for a while now but nothing comes to mind. |
|
Apr 18 |
comment |
Power series solution for a DE Yes, I forgot to mention that but wouldn't we just group the constants together? So we write $c_1-1=c_2$? |
|
Apr 18 |
asked | Power series solution for a DE |
|
Apr 9 |
asked | A logic puzzle involving a balance. |
|
Apr 2 |
accepted | Converting an integral from Cartesian to Polar coordinates. |
