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seen Feb 16 at 23:56

Jul
2
awarded  Curious
Feb
2
comment Finding the dual cone
Thank you for your response however given the simplicity of my question, it's clear I'm a novice. Your response is very textbook-esque, which unfortunately is still somewhat unclear to me. Can you walk through your answer in layman's terms so I might have a chance to understand?
Feb
2
asked Finding the dual cone
Jan
29
awarded  Editor
Jan
29
revised Conjugate of a function
deleted 1 characters in body
Jan
29
asked Conjugate of a function
Jan
28
comment Determining if a function is convex
I see, thanks ..
Jan
28
awarded  Custodian
Jan
28
reviewed Approve suggested edit on Determining if a function is convex
Jan
28
comment Determining if a function is convex
So given $e^{g(x)}$ is convex if $g$ is convex, does it mean that anywhere that $-a \sqrt x $ is not convex then $e^{-a \sqrt x}$ is not convex?
Jan
28
comment Determining if a function is convex
So within the ranges provided for $a$, any value of $\bigtriangledown^2 f(x) $ at the $a$ must be $\succeq 0$ to be convex, correct? In this case $-1 \le a \le 1$ produces negative values so is not convex at those values of $a$...
Jan
28
asked Determining if a function is convex
Nov
25
accepted General solution to $\frac{df}{dx}=3f$
Nov
24
comment General solution to $\frac{df}{dx}=3f$
I see. $f=e^{3x}$ so $\frac{d}{dx}(e^{3x})=3e^{3x}$ which is $3f$.
Nov
24
asked General solution to $\frac{df}{dx}=3f$
Nov
23
awarded  Student
Nov
23
awarded  Scholar
Nov
23
accepted Exponential integration rule
Nov
23
comment Exponential integration rule
There are probably things missing which is probably aiding in my confusion. What I was missing is that $du=(1-b)da; \frac{1}{1-b}du=da$ Thank you.
Nov
23
asked Exponential integration rule