strimp099
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 Mar5 awarded Autobiographer Jul2 awarded Curious Feb2 comment Finding the dual cone Thank you for your response however given the simplicity of my question, it's clear I'm a novice. Your response is very textbook-esque, which unfortunately is still somewhat unclear to me. Can you walk through your answer in layman's terms so I might have a chance to understand? Feb2 asked Finding the dual cone Jan29 awarded Editor Jan29 revised Conjugate of a function deleted 1 characters in body Jan29 asked Conjugate of a function Jan28 comment Determining if a function is convex I see, thanks .. Jan28 awarded Custodian Jan28 reviewed Approve Determining if a function is convex Jan28 comment Determining if a function is convex So given $e^{g(x)}$ is convex if $g$ is convex, does it mean that anywhere that $-a \sqrt x$ is not convex then $e^{-a \sqrt x}$ is not convex? Jan28 comment Determining if a function is convex So within the ranges provided for $a$, any value of $\bigtriangledown^2 f(x)$ at the $a$ must be $\succeq 0$ to be convex, correct? In this case $-1 \le a \le 1$ produces negative values so is not convex at those values of $a$... Jan28 asked Determining if a function is convex Nov25 accepted General solution to $\frac{df}{dx}=3f$ Nov24 comment General solution to $\frac{df}{dx}=3f$ I see. $f=e^{3x}$ so $\frac{d}{dx}(e^{3x})=3e^{3x}$ which is $3f$. Nov24 asked General solution to $\frac{df}{dx}=3f$ Nov23 awarded Student Nov23 awarded Scholar Nov23 accepted Exponential integration rule Nov23 comment Exponential integration rule There are probably things missing which is probably aiding in my confusion. What I was missing is that $du=(1-b)da; \frac{1}{1-b}du=da$ Thank you.