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Jun
30
awarded  Popular Question
May
6
revised Baseball Combinations Problem
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May
6
suggested approved edit on Baseball Combinations Problem
May
6
comment Combinations and Probability Problem
$$\frac{15!}{5!} \neq 10!$$
May
5
accepted Problem with the Birthday Problem
May
5
comment Problem with the Birthday Problem
If we assume any given day is equally likely have someone born on it, then the probability of someone being born on day $q$ is $\frac{1}{365}$. Now, $n$ people, each of which has a $\frac{1}{365}$ chance of being born on day $q$, show up to the party. Since each one being born on $q$ is independent, the chance of $n\vee(n-1)\vee...\vee(n-(n-1))$ being born on $q$ should be $$\frac{1}{365}*n = \frac{n}{365}$$ so even without garunteeing that $n$ people didn't share a birthday, shouldn't the probability of one at the party having birthday $q$ still be $\frac{n}{365}$?
May
5
comment Problem with the Birthday Problem
Doesn't having $q$ be arbitrary cause it to keep track of all of the birthdays represented by definition? I was thinking the analogy would be more like "I stand alone in a room, to ask about the birthday $q$, and let one person in at a time and ask if their birthday is. Then I do this again for every possible value of $q$" If there is no $q$ such that 2 other people have the same birthday, then no one shares a birthday.
May
5
comment Problem with the Birthday Problem
@Demosthene - except $q$ was selected arbitrarily, so if no two people have $q$ as their birthday, then no one in the room shares the same birthday
May
5
comment Problem with the Birthday Problem
@SeyhmusGüngören - care to elaborate?
May
5
asked Problem with the Birthday Problem
Apr
22
accepted Bijection between $\mathbb{Z} \longmapsto \mathbb{R}$
Apr
22
asked Bijection between $\mathbb{Z} \longmapsto \mathbb{R}$
Apr
21
awarded  Notable Question
Dec
9
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Sep
30
awarded  Explainer
Jul
2
awarded  Curious
Jun
23
revised Simplest form of $h'(y)$ given $h(y)= (1-3y^2)^5 \cdot ( y^2 + 2)^6$
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Jun
22
revised Simplest form of $h'(y)$ given $h(y)= (1-3y^2)^5 \cdot ( y^2 + 2)^6$
added 33 characters in body
Jun
22
revised Simplest form of $h'(y)$ given $h(y)= (1-3y^2)^5 \cdot ( y^2 + 2)^6$
added 33 characters in body
Jun
22
answered Simplest form of $h'(y)$ given $h(y)= (1-3y^2)^5 \cdot ( y^2 + 2)^6$