Tag Info

New answers tagged

1

No, it is not. Recall that by the Chern character isomorphism, rational K-theory is periodic rational cohomology, so the cup product on odd rational K-theory doesn't vanish in any situation where the cup product on odd rational cohomology doesn't vanish; the simplest example is $S^1 \times S^1$. The stability argument is irrelevant because the cup product ...



Top 50 recent answers are included